Hi ,
I am working at Unix system,using c lang.
I need c fun which return the day of the week .
For example :
0- Sunday.
1- Monday.
....
10x. (4 Replies)
How to find the Day of the Week of the given Date using perl?
If I have a date in YYY--MM-DD format, how to find the DOW? Based on that, I need to find the following sunday.
Pls help. (5 Replies)
Hi All,
I have date in string format 'YYYY-MM-DD'. I want to know day of the week for this date.
Example. For '2005-08-21' my script should return '0' or Sunday
For '2005-08-22' it should return '1' or Monday
I want piece of code for HP-UX korn shell.
Appreciate reply on this. (5 Replies)
Hi all,
My program is getting date from database (oracle) and am getting that date's day of week also.
In windows its giving one number and different in linux ;)
For Example:
30 - Jun - 2009
Am getting 2 in windows and 3 in Linux.
Am not understanding whats going wrong.. Am... (3 Replies)
Hi all, I am trying to get dow from cal using below script
#! /bin/bash
YEAR=`echo $1 | cut -c 1-4`
MONTH=`echo $1 | cut -c 5-6`
DAY=`echo $1 | cut -c 7-8`
for i in 1 2 3 4 5 6 7
do
dayofweek=`cal $MONTH $YEAR | awk '$i == $DAY {printf("%s","$i")}'`
echo $dayofweek... (4 Replies)
Hi All,
I need to know how to derive the day of the week by passing the value in following format:
Feb 28 2010
The output I'm expecting is Sunday or Sun.
I know, I can use the following code to get the day of the week.
date +%a
But I want to pass the value as a string. Please help... (11 Replies)
In HP-UX the date command does not have the "-d" switch like some other *nixes do. I'm working a simple script to tell me, given the day, month and year what day of the week that falls on.
Assuming valid day, month and year input (I'd perform quality checks on the input separately, but not... (5 Replies)
I have been volunteered by my boss to be the sysadmin for our production redhat server. He asked me to tighten the security to avoid mishaps like "rm -f *" that occured not long ago.
Right now, we have 53 users sudo-ing into the machine and it is an audit nightmare. I am wondering if it... (15 Replies)
Hi everyone,
I have a shell script that merges many files down in to one, then removes unwanted lines, that part is working fine:
#!/bin/bash
FILES=/home/pi/temp/qbd/*
for f in $FILES
do
echo "Processing $f file..."
# take action on each file. $f store current file name
echo... (9 Replies)
Hi All,
I have the below requirement ,
if i give the week number for ex 41 i need to get the date for Monday and thursday for this given week. my expected output is 13/10/2014 (Monday's date) and 16/10/2014 (Thursday's date)
I am using GNU LINUX .
Pls help me with your thoughts.
Thanks in... (7 Replies)
Discussion started by: mohanalakshmi
7 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)