07-03-2009
Need help is manipulating a file with some arithmetic operations using bash script
Friends,
I have a file with contents like:
interface Serial0/4/0/0/1/1/1/1:0
encapsulation mfr
multilink
group 101
Now I need to manipulate the file in such a way that to all the numbers less than 163, 63 gets added and to all numbers greater than 163, 63 gets deducted.(The numbers means the numericals after "group") How do I do this using a bash/shell script?
Thanks
Shrijit
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LEARN ABOUT REDHAT
pvm_joingroup
JOINGROUP(3PVM) PVM Version 3.4 JOINGROUP(3PVM)
NAME
pvm_joingroup - Enrolls the calling process in a named group.
SYNOPSIS
C int inum = pvm_joingroup( char *group )
Fortran call pvmfjoingroup( group, inum )
PARAMETERS
group Character string group name of an existing group.
inum Integer instance number returned by the routine. Instance numbers start at 0 and count up. Values less than zero indicate an
error.
DESCRIPTION
The routine pvm_joingroup enrolls the calling task in the group named group and returns the instance number inum of this task in this
group. If there is an error inum will be negative.
Instance numbers start at 0 and count up. When using groups a (group, inum) pair uniquely identifies a PVM process. This is consistent
with the PVM 2.4 naming schemes. If a task leaves a group by calling pvm_lvgroup and later rejoins the same group, the task is not guaran-
teed to get the same instance number. PVM attempts to reuse old instance numbers, so when a task joins a group it will get the lowest
available instance number. A task can be a member of multiple groups simultaneously.
EXAMPLES
C:
inum = pvm_joingroup( "worker" );
Fortran:
CALL PVMFJOINGROUP( 'group2', INUM )
ERRORS
These error conditions can be returned by pvm_joingroup
PvmSysErr
pvmd was not started or has crashed.
PvmBadParam
giving a NULL group name.
PvmDupGroup
trying to join a group you are already in.
SEE ALSO
pvm_lvgroup(3PVM)
30 August, 1993 JOINGROUP(3PVM)