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Top Forums Shell Programming and Scripting Print to 2 files in awk if statement Post 302330201 by Donkey25 on Tuesday 30th of June 2009 12:23:40 PM
Old 06-30-2009
Print to 2 files in awk if statement

Hi all,

I have some code like this

Code:
awk -F, '{
if ($1==3)
print $2 > "output_file"
print "1" > "new_file"
}' "input_file"

When I check output_file this has the correct values in it. However the new_file has 1 in it for every line in the input_file. If the input file has 20 lins then my new_file will contain 20 1's. I only want it to print 1 if the first field in my input field is 3 - at the moment it prints 1 regardless of what is in the first field.

Can somebody please tell me what I'm doing wrong?

Thanks!
 

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base64(1)						    BSD General Commands Manual 						 base64(1)

NAME
base64 -- Encode and decode using Base64 representation SYNOPSIS
base64 [-d | -h | -v | -D] [-b count] [-i input_file] [-o output_file] DESCRIPTION
base64 encodes and decodes Base64 data, as specified in RFC 4648. With no options, base64 reads raw data from stdin and writes encoded data as a continuous block to stdout. OPTIONS
The following options are available: -b count --break=count Insert line breaks every count characters. Default is 0, which generates an unbroken stream. -d --debug Print verbose log messages during processing. -D --decode Decode incoming Base64 stream into binary data. -h --help Print usage summary and exit. -i input_file --input=input_file Read input from input_file. Default is stdin; passing - also represents stdin. -o output_file --output=output_file Write output to output_file. Default is stdout; passing - also represents stdout. -v --version Print build version and exit. SEE ALSO
openssl(1), wikipedia page <http://en.wikipedia.org/wiki/Base64>, RFC 4648 <http://tools.ietf.org/html/rfc4648> Mac OS X 10.7 February 8, 2011 Mac OS X 10.7
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