06-29-2009
Quote:
Originally Posted by
ua-agent
Options->Remote Login->Enter Host Name.
Where do you see this? I cant see what you mean actually...
9 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hi,
I'm a beginner in unix.As a part of my script i need to remote logon using ssh.
my script run as being asked for password and logons only after the user enters the password correctly. But my script stops executing after that as I login to a different server(different shell if i'm right).... (3 Replies)
Discussion started by: dayanand
3 Replies
2. UNIX for Advanced & Expert Users
Hello all,
I need a script that can run an sftp session into a remote server, and retreive a file. Does anyone know how to pass in the user/password details in a script? I seem to have forgotten (5 Replies)
Discussion started by: Khoomfire
5 Replies
3. Solaris
Hi, Boss
I have a question....
BackGround: i have a shell name xxxLineInput.x
the useage is: xxxLineInput.x -Txxx -Uxxx -Pxxx
when i use the command line..can run normal.
Target: i want to set automatic login, the mean is when i login the as the specifical... (0 Replies)
Discussion started by: surainbow
0 Replies
4. UNIX for Dummies Questions & Answers
I need a script that will let me connect to my hpux server with just a click of the icon without type my username and password. (5 Replies)
Discussion started by: tree740
5 Replies
5. Slackware
I know how to set up KDM or GDM to do automatic login, but is there a way to do it without GDM or KDM or X at all so when I start the machine I am immediately taken to a waiting command prompt? Thanks (5 Replies)
Discussion started by: raidzero
5 Replies
6. Shell Programming and Scripting
I am attempting to create a script that runs automatically upon logging in and opens and places windows in appropriate places. I have the script running such that it starts during login, but I cannot get things how and where I want them. This should be relatively simple, I just can't figure it out... (7 Replies)
Discussion started by: wydileie
7 Replies
7. UNIX for Dummies Questions & Answers
Hi,
how can I set my linux server that it logs in the main user at startup?
I would like to be able to make a restart remotely and be able to connect to the server again afterwards.
The problem is that the server waits for a login and than connects to the network. So at the beginning at... (5 Replies)
Discussion started by: borobudur
5 Replies
8. Solaris
how to login with ssh to remote system with out applying the remote root/user password
with rlogin we can ujse .rhosts file
but with ssh howits possible
plz guide (2 Replies)
Discussion started by: tv.praveenkumar
2 Replies
9. Solaris
On Solaris 11 is it possible to bypass the userid/password requirement to automatically login to the desktop ?
I'm the sole user and it is really not necessary to secure the system.
I have searched this forum and have not found a relevant post. (2 Replies)
Discussion started by: stansaraczewski
2 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)
NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS
--debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)