Hello all,
I have just started doing shell scripting.
I want to read a file which stores the status of my job I have submitted
on a cluster.
The file looks something like this :
========================FILE=============================

crab: Checking the status of all jobs: please wait
crab:
ID STATUS E_HOST EXE_EXIT_CODE JOB_EXIT_STATUS
--------------------------------------------------------------------------------------------
1 Done
2 Done

crab: 2 Total Jobs
=====================================================

The highlighted lines display the status of the jobs. The status shown is done. Whenever it is done I want to give a command which is "getoutput" to retrieve my jobs.
So I want to write a small script which can read this file and whenever it is
done it just retrieves the output.
Could somebody tell me if there is a way to do this using shell script?

This is something which I tried doing but didnt work. "out" is file which stores the output info

==================================line========================================

flag[1]=0
flag[2]=0
cat out | gawk 'BEGIN{i=1;}{if($2=="Done") { $flag[i]=1; }'

if($flag[1]==1 && $flag[2]==1); then
getoutput
fi
================================================================================

But this doesnt seem to work because it seems that its treating flag[1] & flag[2] as local variables inside
gawk.


Thanks
learn_linux