Sponsored Content
Top Forums UNIX for Advanced & Expert Users how do you parse 1 line at a time of file1 ie. line(n) each line into new file Post 302329503 by web_developer on Sunday 28th of June 2009 12:07:11 PM
Old 06-28-2009
Input file dfn and Output file(s) dfn

My input file is a list of html code for products that have a unique key as their id numbers in the description of the code..

test1
<html>(the code for product #####)</html> <==a complete webpage
i wanted to use the cnt value to represent a unique means of createing a new and different file fore each line in he test1 file so in essenct, it is creating a new html file for each line which I have tested and verified is seperated by a carrage return and no tabs or carage returns in the line itself.


filename.txt is another possible input file i tried to used a mv script to change the name of the cnt.html files created by the first script
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

SED help (remove line::parse again::add line)

Aloha! I have just over 1k of users that have permissions that they shouldn't under our system. I need to parse a provided list of usernames, check their permissions file, and strip the permissions that they are not allowed to have. If upon the permissions strip they are left with no permissions,... (6 Replies)
Discussion started by: Malumake
6 Replies

2. Shell Programming and Scripting

cat file1 read line-per-line then grep -A 15 lines down in fileb

STEP 1 # Set variable FILE=/tmp/mainfile SEARCHFILE =/tmp/searchfile # THIS IS THE MAIN FILE. cat /tmp/mainfile Interface Ethernet0/0 "outside", is up, line protocol is up Hardware is i82546GB rev03, BW 100 Mbps Full-Duplex(Full-duplex), 100 Mbps(100 Mbps) MAC address... (6 Replies)
Discussion started by: irongeekio
6 Replies

3. Shell Programming and Scripting

Compare multiple fields in file1 to file2 and print line and next line

Hello, I have two files that I need to compare and print out the line from file2 that has the first 6 fields matching the first 6 fields in file1. Complicating this are the following restrictions 1. file1 is only a few thousand lines at most and file2 is greater than 2 million 2. I need to... (7 Replies)
Discussion started by: gillesc_mac
7 Replies

4. Shell Programming and Scripting

Replacing line 'i' of file1 with line 'j' of file 2

Hi All, As mentioned in the title I have two text files and I would like to replace line number 5 of file #1 with line number 4 of file #2 e.g. file 1 wqwert 4.4464002 3 319 286 369 46.320002 56.150002 45.100002 1 1 1 0.723 (12 Replies)
Discussion started by: f_o_555
12 Replies

5. UNIX for Dummies Questions & Answers

Parsing file, reading each line to variable, evaluating date/time stamp of each line

So, the beginning of my script will cat & grep a file with the output directed to a new file. The data I have in this file needs to be parsed, read and evaluated. Basically, I need to identify the latest date/time stamp and then calculate whether or not it is within 15 minutes of the current... (1 Reply)
Discussion started by: hynesward
1 Replies

6. Shell Programming and Scripting

Using regex's from file1, print line and line after matches in file2

Good day, I have a list of regular expressions in file1. For each match in file2, print the containing line and the line after. file1: file2: Output: I can match a regex and print the line and line after awk '{lines = $0} /Macrosiphum_rosae/ {print lines ; print lines } ' ... (1 Reply)
Discussion started by: pathunkathunk
1 Replies

7. Shell Programming and Scripting

Need a program that read a file line by line and prints out lines 1, 2 & 3 after an empty line...

Hello, I need a program that read a file line by line and prints out lines 1, 2 & 3 after an empty line... An example of entries in the file would be: SRVXPAPI001 ERRO JUN24 07:28:34 1775 REASON= 0000, PROCID= #E506 #1065: TPCIPPR, INDEX= 003F ... (8 Replies)
Discussion started by: Ferocci
8 Replies

8. Shell Programming and Scripting

Ksh: Read line parse characters into variable and remove the line if the date is older than 50 days

I have a test file with the following format, It contains the username_date when the user was locked from the database. $ cat lockedusers.txt TEST1_21062016 TEST2_02122015 TEST3_01032016 TEST4_01042016 I'm writing a ksh script and faced with this difficult scenario for my... (11 Replies)
Discussion started by: humble_learner
11 Replies

9. UNIX for Beginners Questions & Answers

Read 2 file line by line @ same time

HI All, I am aware of reading one file line by line but now my requirement is to read 2 file line by line as below explained. I have 2 files as below file 1 with spaces and file 2 same as file1 but without space and () brackets now i have to read both file line by line and use first line of... (13 Replies)
Discussion started by: abhaydas
13 Replies

10. UNIX for Beginners Questions & Answers

Get an output of lines in pattern 1st line then 10th line then 11th line then 20th line and so on.

Input file: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 (6 Replies)
Discussion started by: Sagar Singh
6 Replies
kreg(8) 						      System Manager's Manual							   kreg(8)

NAME
kreg - Maintains the system file that registers kernel layered products SYNOPSIS
/sbin/kreg -d subset [-c NAME] | -l vendor subset path [-c NAME] OPTIONS
Causes the specified layered product to be loaded or deleted from the NAME.list file for the given name in addition to the /usr/sys/conf/.product.list file. Note that the NAME parameter is case sensitive and must exactly match the NAME prefix for the desired NAME.list file. Deletes the entry for the specified layered product when you remove it from the system. Loads the data that controls how to include the layered product in the kernel build process. DESCRIPTION
The kreg command maintains the /usr/sys/conf/.product.list system file, which registers static kernel layered products. The kreg command creates the file if it does not exist. The file enables system utilities or user supplied commands to locate the kernel parts of a layered product, and it provides information about layered products. The kernel tools use the /usr/sys/conf/.product.list file to build a layered product into the kernel. You can use the file to register a static kernel layered product that has been loaded into the system. The file also can be used by the layered product's Software Control Program (SCP), which is called by the setld command. You copy the /usr/sys/conf/.product.list file into the file that is used to extend the kernel configuration files and that has the follow- ing syntax: /usr/sys/conf/NAME.list The NAME variable specifies the system name that also is used in the system configuration file that has the following syntax: /usr/sys/conf/NAME The doconfig command also will copy the /usr/sys/conf/.product.list file. You can use the -c option to load or delete your layered product into a specific NAME.list file as well as the file. This is useful if you want to load your layered product into a specific NAME.list file without requiring the user to either copy the entire file to the NAME.list file or to manually edit the NAME.list file. The kreg command must be invoked from the root (/) directory. The command can be used only for subsets that are loaded by using the setld command. Also, you must be superuser to use the kreg command. FILES
Contains kernel layered product information. Used to extend the kernel configuration files. SEE ALSO
Commands: doconfig(8), setld(8) System Administration kreg(8)
All times are GMT -4. The time now is 04:31 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy