Hi,
I want to compare two strings using wild cards.
In the file run_test i have
if ; then
cp ../stimulus/default_value.in ../log/$1.log
fi
When I issue the command run_test i2c_default_test in the command line, the cp command is not executed.
Whereas if i give the following code,... (2 Replies)
Hi,
I'm fairly new to UNIX, but hopefully some-one can help me with this:
I am using the following code to find files with the name "example.xml":
find . -name "example.xml" -print
that would print me a list like the example here:
./dir1/dir2/example.xml... (5 Replies)
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
List all files in ~c12100 directory beginning with "BOZO" that end with either "123" or "456"
2. Relevant... (3 Replies)
Hi all,
I have a question..
Here is my requirement..I have 500 files in a path say /a/b/c
I have some numbers in a file which are comma seperated...and I wanted to check if the numbers are present in the FileName in the path /a/b/c..if the number is there in the file that is fine..but if... (1 Reply)
Hi,
So I'm kinda new to shell scripts and the like. I've picked up quite a bit of use from browsing the forums here but ran into a new one that I can't seem to find an answer for.
I'm looking to parse/find a string AND the next 15 or so charachters that follow the string within a text file... (1 Reply)
Hi,
Can anyone let me know the command to know the list of filenames that have string 31 in their 4th and 5th positions inside the file:
grep -l "31" main*.txt
The above grep lists all the files which have 31 at any position but I want filenames having 31 at position 4 and position 5. (8 Replies)
Platforms : Solaris 10 and RHEL 5.6
I always get double quotes , single quotes and asteriks mixed up for find, ls and grep commands.
The below commands retrieve the correct results. But , unders stress , I get all these mixed up :mad: .So, i wanted to get a clear picture.
Please check if... (7 Replies)
Hi,
I have a list of zipped files. I want to grep for a string in all files and get a list of file names that contain the string. But without unzipping them before that, more like using something like gzcat.
My OS is:
SunOS test 5.10 Generic_142900-13 sun4u sparc SUNW,SPARC-Enterprise (8 Replies)
greetings,
below is the find command i am using for some filesystem maintenance:
find /data/Engine \( -type d -name .snapshot -prune -o -type d -wholename "/data/Engine/*/CAE" \
-prune -o -type d -wholename "/data/Engine/*/CAD" -prune -o -name ".*.case" \)\
-mtime +365 -print0 -fls... (5 Replies)
Hello
I would like to get know how to do this:
I got a big file (about 1GB) and I need to find a string (for instance by grep )
and then find all records in this file based on a string.
Thanks for advice.
Martin (12 Replies)
Discussion started by: mape
12 Replies
LEARN ABOUT PHP
datefmt_is_lenient
DATEFMT_IS_LENIENT(3) 1 DATEFMT_IS_LENIENT(3)IntlDateFormatter::isLenient - Get the lenient used for the IntlDateFormatter
Object oriented style
SYNOPSIS
public bool IntlDateFormatter::isLenient (void )
DESCRIPTION
Procedural style
bool datefmt_is_lenient (IntlDateFormatter $fmt)
Check if the parser is strict or lenient in interpreting inputs that do not match the pattern exactly.
PARAMETERS
o $fmt
- The formatter resource.
RETURN VALUES
TRUE if parser is lenient, FALSE if parser is strict. By default the parser is lenient.
EXAMPLES
Example #1
datefmt_is_lenient(3) example
<?php
$fmt = datefmt_create(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'dd/mm/yyyy'
);
echo 'lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
datefmt_set_lenient($fmt,false);
echo 'Now lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
?>
Example #2
OO example
<?php
$fmt = new IntlDateFormatter(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
"dd/mm/yyyy"
);
echo "lenient of the formatter is : ";
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0){
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
$fmt->setLenient(FALSE);
echo 'Now lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
?>
The above example will output:
lenient of the formatter is : TRUE
Trying to do parse('35/13/1971').
Result is : -2147483
Now lenient of the formatter is : FALSE
Trying to do parse('35/13/1971').
Result is :
Error_msg is : Date parsing failed: U_PARSE_ERROR
Error_code is : 9
SEE ALSO datefmt_set_lenient(3), datefmt_create(3).
PHP Documentation Group DATEFMT_IS_LENIENT(3)