As all of us know that while moving a file from Windows to Unix some unwanted ^M characters appear in the file. For my case I have release package in zip format which looks like Module_Name_Tag.zip. It contains some directory structure...like
These all directories have some files within them. The problem is when the ZIP file is build in windows and deployed to the server in Unix environment. Automatically, ^M characters comes into all files.
I can execute
or some perl command like
to remove them but it has to be done repeatedly on all files. As a matter of fact,
I have to 1. Unzip the package 2. Remove characters of all files 3. Zip it again. This looks cumbersome.
Is there any way to remove these characters directly from all files inside the zip?? or I have to conventionally write a script that will unzip , remove and zip the package again?? if it is there any intelligent idea how to proceed? Thanks in advance.
I'm trying to remove the null characters from a file and copy it to std output.
I'm using emacs and I create the following one line bash file (followed by the error messages):
sed -e 's/^@//' <ConfigItemReplicator.install.log
/usr/bin/bash: -c: line 0: unexpected EOF while looking for... (1 Reply)
Here is my code.
for file in *1.3.html ; do mv "$file" `echo $file | tr '.1.3' ''` ; done
For some reason I am getting an error.
mv: file.idlesince.1.3.html and file.idlesince.1.3.html are identical
Could this be done a different way? (5 Replies)
Hi guys,
Hope you are all well.
This is a line of data from a csv file. I have used vi and set the 'set list' option to display the trailing $ character.
"01","Grocery","01006","eat Fish & Spreads"$
I have tried the following commands, but neither of them appear to be working?
1) tr... (13 Replies)
Hi,
I have one file in the following format.
exa_resu_adj.4ge v.47645 PERSONAL INFORMAIONS PVT LTD 31 Dec 2009 04:36 Page 1
SALARY REPORT
Account Account Name CCode Bill No Balance T Amt
----------- ------------ ------- ---------- ------------- -------------
17490001 Mr Ram PM 10... (6 Replies)
Hi All -
I'm building a script wherein it is design to remove characters that are not accepted on a non-unicode database. Examples are the following: ï,¿,½,Â,é, etc.
I can easily sed those characters one-by-one but I there's a problem when other unicode characters are found. Is there any way to... (1 Reply)
I tried using below command
tr -cd "" < InputFile.xml > output.txt ============= This removes all the tabs/newline/extra spaces from a file
it successfully removed all the extra spaces,tabs and new line characters but then the complete file become one record. I want to retain one new line... (1 Reply)
My application generate file but it have special characters in these file.
I would like to clear special characters by vi editor and not use cat /dev/null > to_file
I try to remove characters manually, but I'm can not!
root@MyHost /tmp> ls -l puzzle.txt
-rw-r--r-- 1 root system ... (5 Replies)
i know , the below question has been repeated.
can you guys guide me .
I have the below input
999999 xxxxxxxxxxxxxx 123.45 2013-05-02 08:14 1 1 1 xxxx
999999 xxxxxxxxxxxxxx 123.45 2013-06-02 02:14 1 4 1 dddd
i need to remove from the column 54 to 70 , as like the below output.... (9 Replies)
I want to remove 1st and last two characters of each line of the file
Ex: file1
zzfile1ee
@xfile2:y
qfile3>>
@ file4yy
and redirect to the file called new
Basically file will have any charcter including space, spical character...
Please help.... (7 Replies)
How do I remove the printer escape sequence, the first 5 characters, that occurs on every 33rd line in a file, see hex dump of line 1.
0000 1e 00 00 00 00 0a 0a 0a 20 0a 20 20 20 20 20 20 ....
0010 20 20 20 20 20 20 20 20 20 20 0a 42 49 4c 4c 20
Thanks, (2 Replies)
Discussion started by: jgt
2 Replies
LEARN ABOUT SUSE
zipgrep
ZIPGREP(1L)ZIPGREP(1L)NAME
zipgrep - search files in a ZIP archive for lines matching a pattern
SYNOPSIS
zipgrep [egrep_options] pattern file[.zip] [file(s) ...] [-x xfile(s) ...]
DESCRIPTION
zipgrep will search files within a ZIP archive for lines matching the given string or pattern. zipgrep is a shell script and requires
egrep(1) and unzip(1L) to function. Its output is identical to that of egrep(1).
ARGUMENTS
pattern
The pattern to be located within a ZIP archive. Any string or regular expression accepted by egrep(1) may be used. file[.zip] Path
of the ZIP archive. (Wildcard expressions for the ZIP archive name are not supported.) If the literal filename is not found, the
suffix .zip is appended. Note that self-extracting ZIP files are supported, as with any other ZIP archive; just specify the .exe
suffix (if any) explicitly.
[file(s)]
An optional list of archive members to be processed, separated by spaces. If no member files are specified, all members of the ZIP
archive are searched. Regular expressions (wildcards) may be used to match multiple members:
* matches a sequence of 0 or more characters
? matches exactly 1 character
[...] matches any single character found inside the brackets; ranges are specified by a beginning character, a hyphen, and an end-
ing character. If an exclamation point or a caret (`!' or `^') follows the left bracket, then the range of characters within
the brackets is complemented (that is, anything except the characters inside the brackets is considered a match).
(Be sure to quote any character that might otherwise be interpreted or modified by the operating system.)
[-x xfile(s)]
An optional list of archive members to be excluded from processing. Since wildcard characters match directory separators (`/'),
this option may be used to exclude any files that are in subdirectories. For example, ``zipgrep grumpy foo *.[ch] -x */*'' would
search for the string ``grumpy'' in all C source files in the main directory of the ``foo'' archive, but none in any subdirectories.
Without the -x option, all C source files in all directories within the zipfile would be searched.
OPTIONS
All options prior to the ZIP archive filename are passed to egrep(1).
SEE ALSO egrep(1), unzip(1L), zip(1L), funzip(1L), zipcloak(1L), zipinfo(1L), zipnote(1L), zipsplit(1L)URL
The Info-ZIP home page is currently at
http://www.info-zip.org/pub/infozip/
or
ftp://ftp.info-zip.org/pub/infozip/ .
AUTHORS
zipgrep was written by Jean-loup Gailly.
Info-ZIP 28 February 2005 ZIPGREP(1L)