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Shell Programming and Scripting
trapping error for a grep in for a loop
Post 302328606 by jville on Wednesday 24th of June 2009 06:01:59 PM
06-24-2009
trapping error for a grep in for a loop
How can I trap and print "cannot find the pattern" when the grep is unable to find the specified pattern in the file using the for loop below ?
Any help would be appreciated.
bash3.4> cat test_file
apple
orange
pineapple
blackberry
script:
for x in `grep -n "mango" test_file |cut -d":" -f1`
do
echo $x
done
Any help would be appreciated.
bash3.4> cat test_file
apple
orange
pineapple
blackberry
script:
for x in `grep -n "mango" test_file |cut -d":" -f1`
do
echo $x
done
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LEARN ABOUT MINIX
grep
GREP(1) General Commands Manual GREP(1) NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)