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Top Forums Programming Not able to execute the method based on OS in JAVA Post 302326672 by cbkihong on Thursday 18th of June 2009 11:51:40 AM
Old 06-18-2009
Please consider taking some time for some readings to consolidate your Java knowledge. You don't use equality (==) for string equality tests. You must use the String.equals() method.

e.g. osName.equals("SunOS")

By using == you were comparing two object references and expectedly the equality is false.
 

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UUIDGEN(1)						      General Commands Manual							UUIDGEN(1)

NAME
uuidgen - command-line utility to create a new UUID value SYNOPSIS
uuidgen [-r|-t] DESCRIPTION
The uuidgen program creates (and prints) a new universally unique identifier (UUID) using the libuuid(3) library. The new UUID can reason- ably be considered unique among all UUIDs created on the local system, and among UUIDs created on other systems in the past and in the future. There are two types of UUIDs which uuidgen can generate: time-based UUIDs and random-based UUIDs. By default uuidgen will generate a ran- dom-based UUID if a high-quality random number generator is present. Otherwise, it will chose a time-based UUID. It is possible to force the generation of one of these two UUID types by using the -r or -t options. OPTIONS
-r Generate a random-based UUID. This method creates a UUID consisting mostly of random bits. It requires that the operating system have a high quality random number generator, such as /dev/random. -t Generate a time-based UUID. This method creates a UUID based on the system clock plus the system's ethernet hardware address, if present. CONFORMING TO
OSF DCE 1.1 AUTHOR
uuidgen was written by Andreas Dilger for libuuid. AVAILABILITY
The uuidgen command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/. SEE ALSO
libuuid(3) Linux May 2009 UUIDGEN(1)
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