Hi All,
I want to find the time diffrence between currnt time and "abc.txt" file create time.
I have solve that but if the abc.txt file created last month then is there any process to find the difftent?
Exp:
Create time of abc.txt is "Apr 14 06:48"
and currect date is "May 17 23:47".... (1 Reply)
I have multiple txt files which begin with the word "orders" in folder C:\source. I need to move the files to folder C:\dest and rename them to "process_<date>_<count>"
So for example , if there are 3 files ordersa.txt , ordersb.txt and ordersc.txt in C:\source , after running the script I want... (1 Reply)
I have multiple txt files which begin with the word "orders" in folder C:\source. I need to move the files to folder C:\dest and rename them to "process_<date>_<count>"
So for example , if there are 3 files ordersa.txt , ordersb.txt and ordersc.txt in C:\source , after running the script I want... (7 Replies)
Hi guys,
brand new to this thread and very very new to UNIX...so go easy please!
Anyway I have a file that looks like this:
>>--------------------------------------------------------------------------
Date/Time/Eng. : 2012-06-22 / 00:26 / DS
Reported problem : (SD) ... (5 Replies)
Hi Guys,
I have file A.txt
File A Data
AK1521
AK2536
AK3164
I want create text file of all data above and write some data on each file.
want Output on below folder
/home/kka/out
AK1521.txt
Hi
Welocme (3 Replies)
hi all Please assist i need to add current date as data to load to a database:
the script is as follow:
#!/bin/ksh
DIR=/export/home/yani_m/scripts/scrip_out_put/
DIR2=/export/home/yani_m/scripts/scrip_out_put/calc/
Date=$1
File22="disk_"$Date
Server=$2
iofiles=$DIR"/*"$Date"*_Ynr.dat"... (4 Replies)
I want to add/append the info in the following format to my.txt file.
20130702|abcd20130702.txt FN|SN|DOB
I tried the below script but it throws me some exceptions.
<#!/bin/sh
dt = date '+%y%m%d'members;
echo $dt+|+members+$dt;
/usr/bin/awk -f
BEGIN { FS="|"; OFS="|"; } { print... (6 Replies)
I have created few text file during run time by redirecting the txt file
echo USER_LIST_"$(date '+%d%h%Y')".csv > report_location.txt
report_location.txt is creating in the same location where I run script
home/script
When I try to remove the txt file at the end of the... (3 Replies)
I have a txt file with a list of error messages in a xml tag format, and each error message is separated with a identifier(endresult).Need to split that and copy and create a new html file.Error message has some special character. how to escape the special character and insert my data into the... (7 Replies)
Discussion started by: DevAakash
7 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)