Hi ,
I need to replace the file name extension with txt to csv,i wrote the below script when executing its giving the below error.Please anyone how to do this?
$ a2.sh
mv: *.: cannot access: No such file or directory
./a2.sh: o: bad number
$ vi a2.sh
a2.sh
-----
#!/bin/ksh
txt=$1... (4 Replies)
Hi,
I need a help regarding a small requirement. I have a list of C files. I need to put them in a file but without .c extension.
say if I have the files as file01.c, file02.c, file03.c etc
My file say cfiles should have
file01
file02
file03
...
...
etc
Appreciate your quick help on... (3 Replies)
I am brand new to hp unix systems. I see some files without extension on this system. If I type name of the file it shows me so many detail but does not take me back to command prompt. What are these files and how do I come back to command prompt? Please help (1 Reply)
I have a bunch of bash functions in a folder (~/BASH) that I added to my $PATH so that I can call them from anywhere.
Yesterday I stripped the .sh extension from all of them so that I just type the function name without adding .sh every time. Some of the functions still work. Some of them don't... (7 Replies)
I have a file
n06-z30-sr65-rgdt0p25-varp0.25-8x6drw-test.cmod
and I want to get the extension.
At the moment I have
set filextension = `echo $f | awk 'BEGIN {FS="."} {print $2}'`
which of course does not work as there is a point in varp0.25 (13 Replies)
trying to copy all the files without extension then add
"*.txt" but its not working is there any other way and i do not want to use
cpio -vdump just want to use copy command
FROM=/usr/share/doc
TO=/aleza/doc
#the follow function copies all the files without extensions
call(){
cd $FROM... (3 Replies)
Hi All,
I want to fetch the files based on .done file and display the .csv files and Wil take .csv files for processing.
1.I need to display the .done files from the directory.
2.next i need to search for the .Csv files based on .done file.then move .csv files for the one directory
... (2 Replies)
I currently have a code that find and zip all files in current folder and zip it, the problem is the name of the zip will include the extension as well and I don't want it.
for ex:
Volvo-red.swf -> Volvo-red.swf.zip
find . -maxdepth 1 -type f ! -name ".*" -exec bash -c 'zip -r "$0.zip"... (6 Replies)
Discussion started by: Frozen77
6 Replies
LEARN ABOUT LINUX
gendiff
GENDIFF(1) General Commands Manual GENDIFF(1)NAME
gendiff - utility to aid in error-free diff file generation
SYNOPSIS
gendiff <directory> <diff-extension>
DESCRIPTION
gendiff is a rather simple script which aids in generating a diff file from a single directory. It takes a directory name and a "diff-
extension" as its only arguments. The diff extension should be a unique sequence of characters added to the end of all original, unmodi-
fied files. The output of the program is a diff file which may be applied with the patch program to recreate the changes.
The usual sequence of events for creating a diff is to create two identical directories, make changes in one directory, and then use the
diff utility to create a list of differences between the two. Using gendiff eliminates the need for the extra, original and unmodified
directory copy. Instead, only the individual files that are modified need to be saved.
Before editing a file, copy the file, appending the extension you have chosen to the filename. I.e. if you were going to edit somefile.cpp
and have chosen the extension "fix", copy it to somefile.cpp.fix before editing it. Then edit the first copy (somefile.cpp).
After editing all the files you need to edit in this fashion, enter the directory one level above where your source code resides, and then
type
$ gendiff somedirectory .fix > mydiff-fix.patch
You should redirect the output to a file (as illustrated) unless you want to see the results on stdout.
SEE ALSO diff(1), patch(1)AUTHOR
Marc Ewing <marc@redhat.com>
4th Berkeley Distribution Mon Jan 10 2000 GENDIFF(1)