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Top Forums Shell Programming and Scripting SED - adding blank line after each Range Match Post 302324287 by danmauer on Wednesday 10th of June 2009 11:39:39 AM
Old 06-10-2009
[quote=radoulov;302324253]The braces limit the scope of the following code to the previously matched records (the records that satisfy the range pattern).
So, the G command (append the hold space to the pattern space, in this case the hold space is empty so you get only the newline character)
will apply on for the records that match the pattern /;/ (the last line of your paragraph).

quote]


i understand that the /;/ as part of /;/G means that newline will go after the semicolum... BUT...

i'm refering to the following semicolum , between the G and p

Code:
 
{/;/G;p}

Also..... if {coding} limits the scope to the previous command.... is that the same as using the -e to apply code to just previously execute expression?

Code:
 
sed -e '/select/I,/,/;/!d' -e '/;/G'



Thanks again for your patience with my questions.

-----Post Update-----

Quote:
Originally Posted by radoulov
You could try something like this:

Code:
sed -n '
  /[Ss][Ee][Ll][Ee][Cc][Tt]/,/;/{/;/G;p;}
  ' infile

Some versions of sed support the I (for case Insensitive) flag:

Code:
sed -n '
  /select/I,/;/{/;/G;p}
  ' infile


Thanks, the first worked, but the /I,/ didn't work...

but i had to add back after the select [ ]*$ because: (which works for 1 & 2 below but not 3)

1. i don't want to catch occurences of where select is part of word, (e.g. selection)

2. i want to catch when select is the only word on the line.

3. i want to catch when select is not the only word on the line, and is followed by a space

***** see that i've modified the test data to show you *****

Code:
 
sed -n '/[Ss][Ee][Ll][Ee][Cc][Tt][ ]*$/,/;/{/;/G;p;}'


Last edited by danmauer; 06-10-2009 at 01:07 PM..
 

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