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Top Forums Programming How to get the sizeof char pointer Post 302322235 by pludi on Wednesday 3rd of June 2009 07:24:19 AM
Old 06-03-2009
First, please use [code][/code] where applicable
Code:
using namespace std;
static void cstrCopy(char *x, const char *y);
int main()
{
    char x[19];
    const string y = "UNIX FORUM";
    cstrCopy(x, y.c_str());
    return 0;
}
void cstrCopy(char *x, const char *y)
{
    if (strlen(y) >= sizeof(x)) {
        throw errorException;
    }
    strncpy(x, y, sizeof(x));
}

Second, a C "string" has no information about itself. It's just an array of characters, which is terminated by a null byte by convention. This also means that your two calls to sizeof will always return 4 (size of a pointer). Better add another parameter with the size of the array.
A more intelligent solution would be to malloc() the "C string" in your function, strncpy() the contents of y, and return the pointer to that memory area.
 

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STRCPY(3)						   BSD Library Functions Manual 						 STRCPY(3)

NAME
stpcpy, stpncpy, strcpy, strncpy -- copy strings LIBRARY
Standard C Library (libc, -lc) SYNOPSIS
#include <string.h> char * stpcpy(char * restrict dst, const char * restrict src); char * stpncpy(char * restrict dst, const char * restrict src, size_t len); char * strcpy(char * restrict dst, const char * restrict src); char * strncpy(char * restrict dst, const char * restrict src, size_t len); DESCRIPTION
The stpcpy() and strcpy() functions copy the string src to dst (including the terminating '' character.) The stpncpy() and strncpy() functions copy at most len characters from src into dst. If src is less than len characters long, the remainder of dst is filled with '' characters. Otherwise, dst is not terminated. RETURN VALUES
The strcpy() and strncpy() functions return dst. The stpcpy() and stpncpy() functions return a pointer to the terminating '' character of dst. If stpncpy() does not terminate dst with a NUL character, it instead returns a pointer to dst[n] (which does not necessarily refer to a valid memory location.) EXAMPLES
The following sets chararray to ``abc'': char chararray[6]; (void)strncpy(chararray, "abc", sizeof(chararray)); The following sets chararray to ``abcdef'': char chararray[6]; (void)strncpy(chararray, "abcdefgh", sizeof(chararray)); Note that it does not NUL terminate chararray because the length of the source string is greater than or equal to the length argument. The following copies as many characters from input to buf as will fit and NUL terminates the result. Because strncpy() does not guarantee to NUL terminate the string itself, this must be done explicitly. char buf[1024]; (void)strncpy(buf, input, sizeof(buf) - 1); buf[sizeof(buf) - 1] = ''; This could be better achieved using strlcpy(3), as shown in the following example: (void)strlcpy(buf, input, sizeof(buf)); Note that because strlcpy(3) is not defined in any standards, it should only be used when portability is not a concern. SEE ALSO
bcopy(3), memccpy(3), memcpy(3), memmove(3), strlcpy(3), wcscpy(3) STANDARDS
The strcpy() and strncpy() functions conform to ISO/IEC 9899:1990 (``ISO C90''). The stpcpy() and stpncpy() functions conform to IEEE Std 1003.1-2008 (``POSIX.1''). HISTORY
The stpcpy() function first appeared in FreeBSD 4.4, and stpncpy() was added in FreeBSD 8.0. SECURITY CONSIDERATIONS
The strcpy() function is easily misused in a manner which enables malicious users to arbitrarily change a running program's functionality through a buffer overflow attack. BSD
February 28, 2009 BSD
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