06-02-2009
how to find out the file's name excluding string?
Hello,
Under one directory, I can use below command to find out the file names with string "Export terminated successfully without warnings"
grep -i -l "Export terminated successfully without warnings" *.*
My question is : how I find out the file names without including string
"Export terminated successfully without warnings"
Thank you
Jerry
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LEARN ABOUT DEBIAN
stg-export
STG-EXPORT(1) StGit Manual STG-EXPORT(1)
NAME
stg-export - Export patches to a directory
SYNOPSIS
stg export [options] [<patch1>] [<patch2>] [<patch3>..<patch4>]
DESCRIPTION
Export a range of applied patches to a given directory (defaults to patches-<branch>) in a standard unified GNU diff format. A template
file (defaulting to .git/patchexport.tmpl or ~/.stgit/templates/patchexport.tmpl or /usr/share/stgit/templates/patchexport.tmpl) can be
used for the patch format. The following variables are supported in the template file:
%(description)s - patch description
%(shortdescr)s - the first line of the patch description
%(longdescr)s - the rest of the patch description, after the first line
%(diffstat)s - the diff statistics
%(authname)s - author's name
%(authemail)s - author's e-mail
%(authdate)s - patch creation date
%(commname)s - committer's name
%(commemail)s - committer's e-mail
OPTIONS
-d DIR, --dir DIR
Export patches to DIR instead of the default.
-p, --patch
Append .patch to the patch names.
-e EXTENSION, --extension EXTENSION
Append .EXTENSION to the patch names.
-n, --numbered
Prefix the patch names with order numbers.
-t FILE, --template FILE
Use FILE as a template.
-b BRANCH, --branch BRANCH
Use BRANCH instead of the default branch.
-s, --stdout
Dump the patches to the standard output.
-O OPTIONS, --diff-opts OPTIONS
Extra options to pass to "git diff".
STGIT
Part of the StGit suite - see linkman:stg[1]
StGit 03/13/2012 STG-EXPORT(1)