i have a commad that display the total each directory size in KB.Below the commad and o/p:
ls -ltr | grep ^d | awk '{print $9}' | xargs du -sk
output:
what i want is the proper tab space b/w value and dir.? how to get that.
thanks in advance (10 Replies)
Hello,
Is there a direct command to check if the delimiter in your file is a tab or a space? And how can they be converted from one to another.
Thanks,
G (4 Replies)
Hi All,
Sample records
2157 91128 -rw-r----- 1 arun1 staff 93315072 Aug 23 06:44 /home/arun/my own/file_name.txt
2157 91128 -rw-r----- 1 arun1 staff 93315072 Aug 23 06:44 /home/arun/myown/file name2.txt
i want to print only user name, user group, size, date time stamp, and... (5 Replies)
Hi, I want to read lines from a file, and I'm using two methods
1 use
while read line
do
done<filename
2 use
line=`sed -n '3p' filename`
however, in both of them, I notice that the tab between fields are automatically converted to space
because I want to use awk over the... (10 Replies)
Hi,
I have a space delimited text file but I only want to change the first space to a tab and keep the rest of the spaces intact. How do I go about doing that? Thanks! (3 Replies)
I have a variable sumOfJEOutputFile which is the output file of an SQL command which contains the output of that SQL. The output looks like below:
-----------
58
I am using following code to manipulate the output:
(sed 1,2d $sumOfJEOutputFile > $newTemp1 | sed '$d' $newTemp1)... (4 Replies)
In the below awk the output is space delimited, but it should be tab delimited. Did I not add the correct -F and OFS? Thank you :).
The input file are rather large so I did not include them, but they are tab-delimeted files as well.
awk
awk -F'\t' -v OFS='\t' 'FNR==1 { next }
> ... (2 Replies)
My file looks like
3 33 210.01.10.0 2.1 1211 560 26 45 1298 98763451112 15412323499 INPUT OK
3 233 40.01.10.0 2.1 1451 780 54 99 1876 78787878784 15423210199 CANCEL OK
Aim is to replace the spaces in each line by tab
Used: sed -e 's/ */\t/g'
But I get output like this... (3 Replies)
Discussion started by: sa@@
3 Replies
LEARN ABOUT PHP
db2_escape_string
DB2_ESCAPE_STRING(3) 1 DB2_ESCAPE_STRING(3)db2_escape_string - Used to escape certain charactersSYNOPSIS
string db2_escape_string (string $string_literal)
DESCRIPTION
Prepends backslashes to special characters in the string argument.
PARAMETERS
o $string_literal
- The string that contains special characters that need to be modified. Characters that are prepended with a backslash are x00,
,
, , ', " and x1a.
RETURN VALUES
Returns $string_literal with the special characters noted above prepended with backslashes.
EXAMPLES
Example #1
A db2_escape_string(3) example
Result of using the db2_escape_string(3) function
<?php
$conn = db2_connect($database, $user, $password);
if ($conn) {
$str[0] = "All characters: x00 ,
,
, , ' , " , x1a .";
$str[1] = "Backslash (). Single quote ('). Double quote (")";
$str[2] = "The NULL character must be quoted as well";
$str[3] = "Intersting characters: x1a , x00 .";
$str[4] = "Nothing to quote";
$str[5] = 200676;
$str[6] = "";
foreach( $str as $string ) {
echo "db2_escape_string: " . db2_escape_string($string). "
";
}
}
?>
The above example will output:
db2_escape_string: All characters: ,
,
, \ , ' , " , .
db2_escape_string: Backslash (\). Single quote ('). Double quote (")
db2_escape_string: The NULL character must be quoted as well
db2_escape_string: Intersting characters: , .
db2_escape_string: Nothing to quote
db2_escape_string: 200676
db2_escape_string:
SEE ALSO db2_prepare(3).
PHP Documentation Group DB2_ESCAPE_STRING(3)