I have a set of simple, one columned text files (in thousands).
file1:
a
b
c
d
file 2:
b
c
d
e
and so on. There is a collection of words in another file:
b d
b c d e
I have to find out the set of words (in each row) is present or absent in the given set of files. So, the output would be in matrix form (file*set) like:
1 0
1 1
I have the following code in bash, which is working well, but it involves very high computational cost with the increase of the file and set size. Any suggestion for better checking for the words is much appreciated.
My code segment:
Thank you in advance
Last edited by vidyadhar85; 05-31-2009 at 10:45 AM..
Reason: code tag added
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Discussion started by: my_Perl
6 Replies
LEARN ABOUT DEBIAN
polish
POLISH(5) Debian POLISH(5)NAME
polish - a list of Polish words
DESCRIPTION
/usr/share/dict/polish is an ASCII file which contains an alphabetic list of words, one per line.
FILES
/etc/dictionaries-common/words is a symbolic link to a /usr/share/dict/<language> file. /usr/share/dict/words is a symbolic link to
/etc/dictionaries-common/words, and is the name by which other software should refer to the system word list. See
select-default-wordlist(8) for more information.
The directory /usr/share/dict can contain word lists for many languages, with name of the language in English, e.g., /usr/share/dict/french
and /usr/share/dict/danish contain respectively lists of French and Danish words if they exist. Such lists should be coded using the UTF-8
character set encoding.
SEE ALSO ispell(1), select-default-wordlist(8), and the Filesystem Hierarchy Standard.
HISTORY
The words lists are not specific, and may be generated from any number of sources.
The system word list used to be /usr/dict/words. For compatibility, software should check that location if /usr/share/dict/words does not
exist.
AUTHOR
Word lists are collected and maintained by various authors.
Debian Project March 29th, 2011 POLISH(5)