when I compile above code,it raise following error:
Undefined first referenced
symbol in file
major /var/tmp/ccwkRAdK.o
minor /var/tmp/ccwkRAdK.o
ld: fatal: Symbol referencing errors. No output written to a.out
What raise above error? which head file include major and minor function? How to correct my above code?
To further my fledgling knowledge of C, I am re-writing some of the Unix command set. My current command is an ls-style command.
All works well, except for device files. How do I get the major/minor numbers for the dev files?
I see from the stat struct there are st_rdev and st_dev members. Do... (1 Reply)
Hi
Can anyone tell me what is major number and minor number in the mknod command. Also what these numbers mean.
I have gone through the man pages but still I couldn't understand.
Regards (3 Replies)
would like to order this input based on major.minor.release AND build number
Label abc_def_0.0.3_build_999 2008/08/01 'Created by me.'
Label abc_def_0.0.9_build_1000 2008/08/01 'Created by me.'
Label abc_def_9.0.9_build_10001 2008/08/01 'Created by me.'
Label abc_def_10.9.100_build_2... (4 Replies)
Good evening ...
does anyone of you know how to change major/minor numbers of disk devices ?
I had to migrate from raid1 to raid5 and this messed up my ASM cluster - I know which devices should have which IDs to match the content - but I have no idea how to change it.
Any help would be... (2 Replies)
Hi,
I have line like this :
proj_name/module/trunk/module_1_0
where the first "1" refers to major version and second "0" refers to minor version.
any AWK or command like that so that I can filter out the major and minor ?
like major= command | input line
minor= command |... (4 Replies)
Hi friends, Please let me know if there is any way to find out Major and Minor numbers of virtual file system like below:
/devices 0K 0K 0K 0% /devices
ctfs 0K 0K 0K 0% /system/contract
proc 0K 0K ... (8 Replies)
I want to remove all rows with a minor repeating count less than 30% compared to the major repeating count from my table. The values of a col(starting col 2) can assume is A,T,G,C and N. Each row has at least 2 values and at most 4 repeating values(out of ATGC).
N is considered a missing value... (12 Replies)
Discussion started by: newbie83
12 Replies
LEARN ABOUT DEBIAN
parse_time
PARSE_TIME(3) BSD Library Functions Manual PARSE_TIME(3)NAME
parse_time, print_time_table, unparse_time, unparse_time_approx, -- parse and unparse time intervals
LIBRARY
The roken library (libroken, -lroken)
SYNOPSIS
#include <parse_time.h>
int
parse_time(const char *timespec, const char *def_unit);
void
print_time_table(FILE *f);
size_t
unparse_time(int seconds, char *buf, size_t len);
size_t
unparse_time_approx(int seconds, char *buf, size_t len);
DESCRIPTION
The parse_time() function converts a the period of time specified in into a number of seconds. The timespec can be any number of <number
unit> pairs separated by comma and whitespace. The number can be negative. Number without explicit units are taken as being def_unit.
The unparse_time() and unparse_time_approx() does the opposite of parse_time(), that is they take a number of seconds and express that as
human readable string. unparse_time produces an exact time, while unparse_time_approx restricts the result to only include one units.
print_time_table() prints a descriptive list of available units on the passed file descriptor.
The possible units include:
second, s
minute, m
hour, h
day
week seven days
month 30 days
year 365 days
Units names can be arbitrarily abbreviated (as long as they are unique).
RETURN VALUES
parse_time() returns the number of seconds that represents the expression in timespec or -1 on error. unparse_time() and
unparse_time_approx() return the number of characters written to buf. if the return value is greater than or equal to the len argument, the
string was too short and some of the printed characters were discarded.
EXAMPLES
#include <stdio.h>
#include <parse_time.h>
int
main(int argc, char **argv)
{
int i;
int result;
char buf[128];
print_time_table(stdout);
for (i = 1; i < argc; i++) {
result = parse_time(argv[i], "second");
if(result == -1) {
fprintf(stderr, "%s: parse error
", argv[i]);
continue;
}
printf("--
");
printf("parse_time = %d
", result);
unparse_time(result, buf, sizeof(buf));
printf("unparse_time = %s
", buf);
unparse_time_approx(result, buf, sizeof(buf));
printf("unparse_time_approx = %s
", buf);
}
return 0;
}
$ ./a.out "1 minute 30 seconds" "90 s" "1 y -1 s"
1 year = 365 days
1 month = 30 days
1 week = 7 days
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds
1 second
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 31535999
unparse_time = 12 months 4 days 23 hours 59 minutes 59 seconds
unparse_time_approx = 12 months
BUGS
Since parse_time() returns -1 on error there is no way to parse "minus one second". Currently "s" at the end of units is ignored. This is a
hack for English plural forms. If these functions are ever localised, this scheme will have to change.
HEIMDAL October 31, 2004 HEIMDAL