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Full Discussion: 32bit Linux vs 64 bit Linux
Operating Systems Linux Red Hat 32bit Linux vs 64 bit Linux Post 302318958 by robsonde on Saturday 23rd of May 2009 12:51:23 AM
Old 05-23-2009
Any 32 bit OS will only see / use 3.5GB of RAM.

Remember that in the absence of the 64 bit support, the OS memory manager is limited to a 4GB physical address space. Most of that address space is filled with RAM, but not all of it. Memory-mapped devices (such as your video card) will use some of that physical address space, as will the BIOS ROMs. After all the non-memory devices have had their say, there will be less than 4GB of address space available for RAM below the 4GB physical address boundary.

the motherboard assigned the ROMs and the hardware devices to the physical address space between 3.5GB and 4GB (occupying about 0.5GB of address space). When you start plugging in your memory chips, then, they are assigned physical addresses starting at the bottom, and then skip over the address space that has already been assigned to the hardware and ROM, then resume.

On this imaginary system, then, the 0.5GB of address space used for hardware and ROMs causes that much memory to get shoved upwards, and it ends up above the 4GB boundary. Without 64 bit support, the processor is capable only of addressing memory below the 4GB boundary, which means that the memory above that boundary is inaccessible. It's consuming electricity but isn't doing anything.

The solution is to go to 64-bit OS so that the processor can access the physical address space above the 4GB boundary.

So why don't we just map the ROMs and the hardware devices to space above 4GB??
then the CPU can't access the IO devices so you have system with 4GB of RAM and no video card......

any questions??
 

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svatophys(9r)															     svatophys(9r)

NAME
svatophys - General: Converts a system virtual address to a physical address SYNOPSIS
kern_return_t svatophys( vm_offset_t kern_addr, vm_offset_t *phys_addr ); ARGUMENTS
Specifies the kernel virtual address. Specifies a pointer to the physical address to be filled in. DESCRIPTION
The svatophys routine converts a system virtual address to the corresponding physical address. All address and data structure manipulation done within the kernel is performed using system virtual addresses. Typically, system virtual addresses are a means of mapping physical memory and I/O space, which often consists of device registers and DMA buffers. In contrast to this, devices are usually unaware of any virtual addressing and for this reason use physical addresses. You use the svatophys routine to perform this address translation. As an example of where you can use this address translation, a disk device driver can use DMA buffers to transfer blocks of data to the disk (for the case of a write operation). The data to be written to disk is present in system memory at a system virtual address known to the driver. To initiate the DMA operation, the disk driver can set up a command packet to specify a write operation to the underlying disk controller hardware. This write command packet contains (among other things) the location of the DMA buffer as a physical address and the length of the buffer. Here, the driver calls the svatophys routine to translate the system virtual address of the DMA buffer to a physical address in the command packet issued to the disk driver. RETURN VALUES
The svatophys routine returns the following: The address translation has been completed successfully. Unable to perform address transla- tion. This value indicates that the address specified by the kern_addr argument is not a valid kernel or system virtual address. svatophys(9r)
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