Hi,
I have a huge file of bibliographic records in some standard format.I need a script to do some repeatable task as follows:
1. Needs to create folders as the strings starts with "item_*" from the input file
2. Create a file "contents" in each folders having "license.txt(tab... (5 Replies)
Hi All,
HP-UX dev4 B.11.11 U 9000/800 3251073457
I need to copy huge data from windows text file to vi editor. when I tried copy huge data, the format of data is not preserverd and appered to scatterd through the vi, something like give below. Please let me know, how can I correct this?
... (18 Replies)
Hi,
I have to search a number in a very long listing of files.the total size of the files in which I have to search is 10 Tera Bytes.
How to search a number in such a huge amount of data effectively.I used fgrep but it is taking many hours to search. Is there any other feasible solution to... (3 Replies)
Hi All,
My disk usage show 100 % . When I check “df –kh” it shows my root partition is full. But when I run the “du –skh /” shows only 7 GB is used.
Filesystem Size Used Avail Use% Mounted on
/dev/sda1 30G 28G 260MB 100% /
How I can identify who is using the 20 GB of memory.
Os: Centos... (10 Replies)
Hi Friends,
I have a file with sample amount data as follows:
-89990.3456
8788798.990000128
55109787.20
-12455558989.90876
I need to exclude the '-' symbol in order to treat all values as an absolute one and then I need to sum up.The record count is around 1 million.
How... (8 Replies)
Dear all ,
I found that if we work with thousands line of data, awk does not work perfectly. It will cut hundreds line (others are deleted) and works only on the remain data.
I used this command : awk '$1==1{$1="Si"}{print>FILENAME}' coba.xyz to change value of first column whose value is 1... (4 Replies)
Dear Experts,
I would like to know what's the best method for copy data around 3 mio (spread in a hundred folders, size each file around 1kb) between 2 servers?
I already tried using Rsync and tar command. But using these command is too long.
Please advice.
Thanks
Edy (11 Replies)
HI Guys,
I have Big XML file with Below Format :-
Input :-
<pokl>MKL=1,FN=1,GBNo=B10C</pokl>
<d>192</d>
<d>315</d>
<d>35</d>
<d>0,7,8</d>
<pokl>MKL=1,dFN=1,GBNo=B11C</pokl>
<d>162</d>
<d>315</d>
<d>35</d>
<d>0,5,6</d>
<pokl>MKL=1,dFN=1,GBNo=B12C</pokl>
<d>188</d> (4 Replies)
Optimization shell/awk script to aggregate (sum) for all the columns of Huge data file
File delimiter "|"
Need to have Sum of all columns, with column number : aggregation (summation) for each column
File not having the header
Like below -
Column 1 "Total
Column 2 : "Total
...
...... (2 Replies)
Discussion started by: kartikirans
2 Replies
LEARN ABOUT SUNOS
mlib_imagenormcrosscorrel
mlib_ImageNormCrossCorrel(3MLIB)mlib_ImageNormCrossCorrel(3MLIB)NAME
mlib_ImageNormCrossCorrel - normalized cross correlation
SYNOPSIS
cc [ flag... ] file... -lmlib [ library... ]
#include <mlib.h>
mlib_status mlib_ImageNormCrossCorrel(mlib_d64 *correl, const mlib_image *img1, const mlib_image *img2, const mlib_d64 *mean2, const
mlib_d64 *sdev2);
The mlib_ImageNormCrossCorrel() function computes the normalized cross-correlation coefficients between a pair of images, on a per-channel
basis.
It uses the following equations:
w-1 h-1
SUM SUM (d1[x][y][i] * d2[x][y][i])
x=0 y=0
correl[i] = -------------------------------------
s1[i] * s2[i]
d1[x][y][i] = img1[x][y][i] - m1[i]
d2[x][y][i] = img2[x][y][i] - m2[i]
1 w-1 h-1
m1[i] = ----- * SUM SUM img1[x][y][i]
w*h x=0 y=0
1 w-1 h-1
m2[i] = ----- * SUM SUM img2[x][y][i]
w*h x=0 y=0
w-1 h-1
s1[i] = sqrt{ SUM SUM (img1[x][y][i] - m1[i])**2 }
x=0 y=0
w-1 h-1
s2[i] = sqrt{ SUM SUM (img2[x][y][i] - m2[i])**2 }
x=0 y=0
where w and h are the width and height of the images, respectively; m1 and m2 are the mean arrays of the first and second images, respec-
tively; s1 and s2 are the un-normalized standard deviation arrays of the first and second images, respectively.
In usual cases, the normalized cross-correlation coefficient is in the range of [-1.0, 1.0]. In the case of (s1[i] == 0) or (s2[i] == 0),
where a constant image channel is involved, the normalized cross-correlation coefficient is defined as follows:
#define signof(x) ((x > 0) ? 1 : ((x < 0) ? -1 : 0))
if ((s1[i] == 0.) || (s2[i] == 0.)) {
if ((s1[i] == 0.) && (s2[i] == 0.)) {
if (signof(m1[i]) == signof(m2[i]) {
correl[i] = 1.0;
} else {
correl[i] = -1.0;
}
} else {
correl[i] = -1.0;
}
}
The two images must have the same type, the same size, and the same number of channels. They can have 1, 2, 3 or 4 channels. They can be
of type MLIB_BYTE, MLIB_SHORT, MLIB_USHORT or MLIB_INT.
If (mean2 == NULL) or (sdev2 == NULL), then m2 and s2 are calculated in this function according to the formulas shown above. Otherwise,
they are calculated as follows:
m2[i] = mean2[i];
s2[i] = sdev2[i] * sqrt(w*h);
where mean2 and sdev2 can be the output of mlib_ImageMean() and mlib_ImageStdDev(), respectively.
The function takes the following arguments:
correl Pointer to normalized cross correlation array on a channel basis. The array must be the size of channels in the images.
correl[i] contains the cross-correlation of channel i.
img1 Pointer to first image.
img2 Pointer to second image.
mean2 Pointer to the mean array of the second image.
sdev2 Pointer to the standard deviation array of the second image.
The function returns MLIB_SUCCESS if successful. Otherwise it returns MLIB_FAILURE.
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Interface Stability |Evolving |
+-----------------------------+-----------------------------+
|MT-Level |MT-Safe |
+-----------------------------+-----------------------------+
mlib_ImageAutoCorrel(3MLIB), mlib_ImageAutoCorrel_Fp(3MLIB), mlib_ImageCrossCorrel(3MLIB), mlib_ImageCrossCorrel_Fp(3MLIB), mlib_ImageNorm-
CrossCorrel_Fp(3MLIB), attributes(5)
23 May 2005 mlib_ImageNormCrossCorrel(3MLIB)