05-18-2009
script takes the whole filename instead of just extension
I am running my script from "/abc/" this path and it has no ".csv files" but has a ".txt" files namely temp1.txt
My script goes as below, wherein it is suppose to find files with *.txt extension and *.csv extension in another path namely "/abc/xyz/":
#!/bin/ksh
PATH1="/abc/xyz/"
value="*.csv *.txt"
for THISTEMPLATE in $value
do
THISTEMPLATE=`echo "$THISTEMPLATE" | tr "%" "?"`
echo "thistemp = $THISTEMPLATE"
for OLDFILE in `find $PATH1 -name "$THISTEMPLATE" -type f`
do
echo "oldfile= $OLDFILE"
done
done
>OUTPUT:
thistemp = *.csv
thistemp = temp1.txt
But if you see the output the variable contains the filename "temp1.txt" instead of just "*.txt", how can i modify the script so that
the variable THISTEMPLATE takes only *.txt instead of the whole filename.
Last edited by wolverine999; 05-18-2009 at 02:12 PM..
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LEARN ABOUT PHP
ziparchive.open
ZIPARCHIVE.OPEN(3) 1 ZIPARCHIVE.OPEN(3)
ZipArchive::open - Open a ZIP file archive
SYNOPSIS
mixed ZipArchive::open (string $filename, [int $flags])
DESCRIPTION
Opens a new zip archive for reading, writing or modifying.
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o $flags
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o ZipArchive::OVERWRITE
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RETURN VALUES
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o ZipArchive::ER_EXISTS File already exists.
o ZipArchive::ER_INCONS Zip archive inconsistent.
o ZipArchive::ER_INVAL Invalid argument.
o ZipArchive::ER_MEMORY Malloc failure.
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PHP Documentation Group ZIPARCHIVE.OPEN(3)