Hi,
Please help to share your thought about how to perfrom summation for particular delimited field, and output to the particular file based on
-rw-r--r-- 1 abc other 3094 Oct 19 09:40 0132019832-ps5_online_cdrm.unl
-rw-r--r-- 1 abc other 1588 Oct 19 09:47... (2 Replies)
Help plz
Does any one have any idea how to compare interval ranges of 2 files.
finding 1-4 (1,2,3,4) of input2 in input1 of same key "a" values (5-10, 30-40, 45-60, 80-90, 100-120 ). Obviously 1-4 is not one of the range with in input1 a. so it should give out of range.
finding 30-33(31,32,33)... (1 Reply)
Hi All,
I need to sum values in a row.
eg:
input is: sum,value1,value2,value3,.....,value N
Required Output: sum,<summation of N values>
Please help me... (1 Reply)
Hello Guys
Please find my below requirement
I have a flat file with column headers in first line and data
The structure like below
col1 col2 col3
A 1 2
B 3 4
C 5 6
Say I have to take the summation of col2 (that will depend on the... (2 Replies)
Hello Guru s
I need your kind help to solve my below issue
I have a directory of flat files and have to calculate sum of some columns from the flat file .
Say for flat file 302 I need the column summation of 2 and 3 rd column
For flat file 303 I need the column summation of 5 and... (2 Replies)
Hi
I am executing below command to do summation on 46th coloumn.
cat File1| awk -F"|" '{p += $46} END { printf"Column Name | SUM | " p}'
I am getting output as
Column Name | SUM | 1.01139e+10
Here I want output in Proper decimal format. Can someone tell me what change is required for same? (1 Reply)
hi guys,
i have a script that basically just sums up the values of 2 particular columns in a file, grouped by the columns specified as well
The script is quite long, but it's basically just repetitive.. just for each condition.
This script only accepts one type of input file.
... (22 Replies)
I have three folders named f1, f2 and f3. The file names are same in all these folders. I would like to get the summation of the second column from all files. How can I do this ?
file1 in f1 folder
143 143.69 60.2 81.30 40.4 62.39 166.3 83.38 107.2 60.30 37.5
144 192.62 107.9... (3 Replies)
Hi All ,
I am having an input file as stated below
Input file
6 ddk/djhdj/djhdj/Q 10 0.5
dhd/jdjd.djd.nd/QB 01 0.5
hdhd/jd/jd/jdj/Q 10 0.5
512 hd/hdh/gdh/Q 01 0.5
jdjd/jd/ud/j/QB 10 0.5
HD/jsj/djd/Q 01 0.5
71 hdh/jjd/dj/jd/Q 10 0.5
... (5 Replies)
Discussion started by: kshitij
5 Replies
LEARN ABOUT DEBIAN
mrtg-logfile
MRTG-LOGFILE(1) mrtg MRTG-LOGFILE(1)NAME
mrtg-logfile - description of the mrtg-2 logfile format
SYNOPSIS
This document provides a description of the contents of the mrtg-2 logfile.
OVERVIEW
The logfile consists of two main sections.
The first Line
It stores the traffic counters from the most recent run of mrtg.
The rest of the File
Stores past traffic rate averates and maxima at increassing intervals.
The first number on each line is a unix time stamp. It represents the number of seconds since 1970.
DETAILS
The first Line
The first line has 3 numbers which are:
A (1st column)
A timestamp of when MRTG last ran for this interface. The timestamp is the number of non-skip seconds passed since the standard UNIX
"epoch" of midnight on 1st of January 1970 GMT.
B (2nd column)
The "incoming bytes counter" value.
C (3rd column)
The "outgoing bytes counter" value.
The rest of the File
The second and remaining lines of the file contains 5 numbers which are:
A (1st column)
The Unix timestamp for the point in time the data on this line is relevant. Note that the interval between timestamps increases as you
progress through the file. At first it is 5 minutes and at the end it is one day between two lines.
This timestamp may be converted in OpenOffice Calc or MS Excel by using the following formula
=(x+y)/86400+DATE(1970;1;1)
(instead of ";" it may be that you have to use "," this depends on the context and your locale settings)
you can also ask perl to help by typing
perl -e 'print scalar localtime(x),"
"'
x is the unix timestamp and y is the offset in seconds from UTC. (Perl knows y).
B (2nd column)
The average incoming transfer rate in bytes per second. This is valid for the time between the A value of the current line and the A
value of the previous line.
C (3rd column)
The average outgoing transfer rate in bytes per second since the previous measurement.
D (4th column)
The maximum incoming transfer rate in bytes per second for the current interval. This is calculated from all the updates which have
occured in the current interval. If the current interval is 1 hour, and updates have occured every 5 minutes, it will be the biggest 5
minute transfer rate seen during the hour.
E (5th column)
The maximum outgoing transfer rate in bytes per second for the current interval.
AUTHOR
Butch Kemper <kemper@bihs.net> and Tobias Oetiker <tobi@oetiker.ch>
2.17.4 2012-01-12 MRTG-LOGFILE(1)