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Full Discussion: Extracting a regex with awk
Top Forums Shell Programming and Scripting Extracting a regex with awk Post 302317017 by Gee-Money on Sunday 17th of May 2009 06:47:20 PM
Old 05-17-2009
From the grep man page:

-o, --only-matching
Show only the part of a matching line that matches PATTERN.


In the words of the Kool-Aid guy....Ohhh-Yeeeaah!
 

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GREPJAR(1)								GNU								GREPJAR(1)

NAME
grepjar - search files in a jar file for a pattern SYNOPSIS
grepjar [-bcinsw] -e PATTERN | PATTERN files... DESCRIPTION
The "grepjar" program can be used to search files in a jar file for a pattern. OPTIONS
-b Print byte offset of match. -c Print number of matches. -i Compare case-insensitively. -n Print line number of each match. -s Suppress error messages. -w Force PATTERN to match only whole words. -e PATTERN Use PATTERN as regular expression. --help Print help, then exit. -V --version Print version number, then exit. SEE ALSO
fastjar(1), gcj(1), gij(1), gfdl(7) and the Info entry for gcj. COPYRIGHT
Copyright (C) 2002, 2007, 2008 Matthias Klose Permission is granted to copy, distribute and/or modify this document under the terms of the GNU General Public License as published by the Free Software Foundation; either version 2, or (at your option) any later version. A copy of the license is included in the man page gfdl(7). 0.97 2008-10-16 GREPJAR(1)
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