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Top Forums Shell Programming and Scripting How to assign the result of a SQL command to more than one variable in shell script. Post 302313890 by little_wonder on Wednesday 6th of May 2009 10:04:07 PM
Old 05-06-2009
MySQL

Thanks its working 5n for me
 

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FBSQL_NEXT_RESULT(3)							 1						      FBSQL_NEXT_RESULT(3)

fbsql_next_result - Move the internal result pointer to the next result

SYNOPSIS
bool fbsql_next_result (resource $result) DESCRIPTION
When sending more than one SQL statement to the server or executing a stored procedure with multiple results will cause the server to return multiple result sets. This function will test for additional results available form the server. If an additional result set exists it will free the existing result set and prepare to fetch the words from the new result set. PARAMETERS
o $ result -A result identifier returned by fbsql_query(3) or fbsql_db_query(3). RETURN VALUES
Returns TRUE if an additional result set was available or FALSE otherwise. EXAMPLES
Example #1 fbsql_next_result(3) example <?php $link = fbsql_connect("localhost", "_SYSTEM", "secret"); fbsql_select_db("MyDB", $link); $SQL = "Select * from table1; select * from table2;"; $rs = fbsql_query($SQL, $link); do { while ($row = fbsql_fetch_row($rs)) { } } while (fbsql_next_result($rs)); fbsql_free_result($rs); fbsql_close($link); ?> PHP Documentation Group FBSQL_NEXT_RESULT(3)
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