05-05-2009
if using vi
for ^Z, type ctrl+v+z
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
Hello,
I am attempting to remove all the ^M characters in a file in VI.
The command I am using is
:1,$s/^V^M//g
but it doesn't work, saying 'substitute pattern match failed'.
Any ideas why?
Jules (2 Replies)
Discussion started by: julesinbath
2 Replies
2. UNIX for Dummies Questions & Answers
HI i am having a file this
(sys19:pnlfct:/pfact/temp>) cat temp_sand
1234567890
1234567890
1234567890
1234567890
I want to make this file as
(sys19:pnlfct:/pfact/temp>) cat temp_sand
1456789023
1456789023
1456789023
1456789023
just take the 2nd and 3rd position and put it... (5 Replies)
Discussion started by: arunkumar_mca
5 Replies
3. Shell Programming and Scripting
How can I remove the last character from each line of a file?
This must be done without "funny" characters, as I want to transfer the code to/from Windows.
Any ideas? (17 Replies)
Discussion started by: cjhancock
17 Replies
4. UNIX for Dummies Questions & Answers
Dear Members,
Problem is suppose i have 50 lines in a file, 40 lines last character is "\" and the remaining 10 lines are good(i mean these 10 lines do not have "\" character)
How can i remove this character from the file.
Thanks (1 Reply)
Discussion started by: sandeep_1105
1 Replies
5. UNIX for Dummies Questions & Answers
Hi,
I have a Linux file which has content as sh (0 Replies)
Discussion started by: bhuvanas
0 Replies
6. Shell Programming and Scripting
Hi,
My file has this special character "^M"
I would like to remove this characters.
eg:
abc,abc,^M
i tried using sed but doesnt work.
i used octal dump command to see special character it returns following:
015
\r
Appreciate your reply. (6 Replies)
Discussion started by: pinnacle
6 Replies
7. Shell Programming and Scripting
I have a file like this:
DDD_ABCDE2AB2_1104081408.104480
I need to remove the 1 after the . in the file name so that it reads:
DDD_ABCDE2AB2_1104081408.04480
Having some difficulty getting the command to work. I tried using
cut -d 26
but that just doesn't work. (3 Replies)
Discussion started by: bbbngowc
3 Replies
8. UNIX for Dummies Questions & Answers
I need help removing the last character of every line if it is a certain character. For example I need to get rid of a % character if it is in the last position.
Input:
aaa%
%bbb
ccc
d%dd%
Output should be:
aaa
%bbb
ccc
d%dd
I tried this but it gets rid of all of the % characters.... (5 Replies)
Discussion started by: raptor25
5 Replies
9. Shell Programming and Scripting
Hi below is my file.
cat input.dat
101,abhilash,1000
102,prave
en,2000
103,partha,4
000
10
4,naresh,5000
(its just a example file)
and my output should be:
101,abhilash,1000
102,praveen,2000
103,partha,4000
104,naresh,5000
below is my code
cat input.dat |tr -d '\n' >... (6 Replies)
Discussion started by: abhilash_nakka
6 Replies
10. Shell Programming and Scripting
Hello guys,
I would need to remove the last character ")" of a specific line. This can be from any line. Your help is appreciated. Below is the line.
HOSTNAME=(DESCRIPTION=(ADDRESS=(PROTOCOL=TCP))
Please help. (6 Replies)
Discussion started by: sang8g
6 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)
NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS
--debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)