another thing you can try on the remote side is to modify the .profile or whatever .file your shell uses and wrap the commands in this
another thought is that the first two lines are actually being printed from the local machine when you run the su command but before ssh starts to execute. try the tty -s solution there first.
Last edited by frank_rizzo; 04-30-2009 at 11:17 PM..
Reason: forgot code tags
hi,
while we writing shell script, i want to ignore interrupts likes - "control + C" or "control + \"
coz I just print out the message.
how can i do this?
thanks
min (3 Replies)
I'm using the following command to zip a project file, but when it finishes, the resulting zip file contains all the directories above the file I wanted zipped, myapp.app, each one empty until you get to the actual app.
zip -r myapp.app.zip ... (0 Replies)
As of a week ago i thought a shell was somthing found on a beach.
I'm a virgin when it comes to scripting and i'm having a really bad time here.
What i need to do is prompt for a group number
grep the /etc/groups to get the GID and name
if it exists i want to prompt the user for... (3 Replies)
Well, I think I've managed to take two different issues and conglomerate them into and embarrasing mess.
#!/bin/bash
# Set some variables
dir1=/path/that/isnt/variable/$variabledir/dir/
dir2=/path/that/isnt/variable/$variabledir/important/"$variabledir"-subdirectory/path/
echo "Gimme... (7 Replies)
Hello
I try to store stderr into a variable, then if this var is not empty i send an email and stop my script.
I think my problem is due of "<$dump" into my command line.
my bad command line (see samples below on this post)
if ! $returnedStr ;
then
echo ERROR READING DUMP: ... (8 Replies)
I'm trying to make a dialog window that prints the output of grep that takes the output of find. Unfortunately my nested backticks don't work.
Here is the dialog window:
dialog --stdout --title "test" --backtitle "test" --msgbox "Test:\n `grep -l "${tablica}" `find $string``" 16 60I think I... (2 Replies)
I have the basic command written in bash
for element in 1 2
do
if ]; then
set el = "t"
else
set el = "p"
fi
done
but i get the following error
syntax error near unexpected token `for'
` for element in 1 2'
What should i do differently? (3 Replies)
The variables given are already defined ($file1-$file3, $obsid1-$obsid3, and $n=3). When I go to run the code, the terminal outputs "Missing }." I believe the error is with the nesting of variables. It would save a lot of time getting this while loop working.
set i = 1
while (${i} <=... (5 Replies)
Discussion started by: ojdefdidit
5 Replies
LEARN ABOUT SUSE
ssh-copy-id
SSH-COPY-ID(1) General Commands Manual SSH-COPY-ID(1)NAME
ssh-copy-id - install your public key in a remote machine's authorized_keys
SYNOPSIS
ssh-copy-id [-i [identity_file]] [user@]machine
DESCRIPTION
ssh-copy-id is a script that uses ssh to log into a remote machine (presumably using a login password, so password authentication should be
enabled, unless you've done some clever use of multiple identities)
It also changes the permissions of the remote user's home, ~/.ssh, and ~/.ssh/authorized_keys to remove group writability (which would oth-
erwise prevent you from logging in, if the remote sshd has StrictModes set in its configuration).
If the -i option is given then the identity file (defaults to ~/.ssh/id_rsa.pub) is used, regardless of whether there are any keys in your
ssh-agent. Otherwise, if this:
ssh-add -L
provides any output, it uses that in preference to the identity file.
If the -i option is used, or the ssh-add produced no output, then it uses the contents of the identity file. Once it has one or more fin-
gerprints (by whatever means) it uses ssh to append them to ~/.ssh/authorized_keys on the remote machine (creating the file, and directory,
if necessary)
SEE ALSO ssh(1), ssh-agent(1), sshd(8)OpenSSH 14 November 1999 SSH-COPY-ID(1)