I have a pel script running as root that needs to read the contents of a file on a remote system, I have an ssh trust relationship as a particular user but not as root.
I then need to write back out to that file again to change it's content a bit.
On the surface this seemed really easy but I'm getting tangled up in all the layers required to actually do this.
I'm tryint to do the following:
This seems to work pretty well but it's including the login banner at the top of the "file" returned and I can't seem to get it to ignore it.
I've tried including '2> /dev/null' at various points in the line to no avail.
In order to get to the bottom of this, I've abstracted that part out into a shell script called 'remote-cat.sh:
Which returns the login header followed by the file contents:
If I change my script to be:
I only see the header:
But if I change the script to use 2> /dev/null:
I just get the header and text combined again like before.
So, where am I going wrong here? Or is there better way to do this in perl without having to do all the su, ssh, cat rubbish?
hi,
while we writing shell script, i want to ignore interrupts likes - "control + C" or "control + \"
coz I just print out the message.
how can i do this?
thanks
min (3 Replies)
I'm using the following command to zip a project file, but when it finishes, the resulting zip file contains all the directories above the file I wanted zipped, myapp.app, each one empty until you get to the actual app.
zip -r myapp.app.zip ... (0 Replies)
As of a week ago i thought a shell was somthing found on a beach.
I'm a virgin when it comes to scripting and i'm having a really bad time here.
What i need to do is prompt for a group number
grep the /etc/groups to get the GID and name
if it exists i want to prompt the user for... (3 Replies)
Well, I think I've managed to take two different issues and conglomerate them into and embarrasing mess.
#!/bin/bash
# Set some variables
dir1=/path/that/isnt/variable/$variabledir/dir/
dir2=/path/that/isnt/variable/$variabledir/important/"$variabledir"-subdirectory/path/
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Hello
I try to store stderr into a variable, then if this var is not empty i send an email and stop my script.
I think my problem is due of "<$dump" into my command line.
my bad command line (see samples below on this post)
if ! $returnedStr ;
then
echo ERROR READING DUMP: ... (8 Replies)
I'm trying to make a dialog window that prints the output of grep that takes the output of find. Unfortunately my nested backticks don't work.
Here is the dialog window:
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I have the basic command written in bash
for element in 1 2
do
if ]; then
set el = "t"
else
set el = "p"
fi
done
but i get the following error
syntax error near unexpected token `for'
` for element in 1 2'
What should i do differently? (3 Replies)
The variables given are already defined ($file1-$file3, $obsid1-$obsid3, and $n=3). When I go to run the code, the terminal outputs "Missing }." I believe the error is with the nesting of variables. It would save a lot of time getting this while loop working.
set i = 1
while (${i} <=... (5 Replies)