Hi,
I am new to UNIX Scripting. I have been trying to use the CUT command to retrieve part of the header from a file and assign it to a variable. I have tried searching a lot, but I am still unsuccessful.
Sample Header: HJAN BALANCE 20090616
I need to retrieve the date here, which always... (10 Replies)
greetings all,
I am have a heck of a time trying to accomplish a very simple thing. I have an array of "shortname<spaces>id" created from a dscl output. I want to assign shortname=word1 and id=word2. I have tried
shortname=$(${textArray} | awk '{print $1}') - and get 'awk : cannot open... (3 Replies)
I'm running a bash script query and assigning the output to a variable like this:
exists=`mysql -u $USER_NAME --password=$PASSWORD -D "somedb" \
-e "SELECT * FROM somedb.sometable WHERE field1 ='$a' \
AND field2 ='$b' LIMIT 0 , 30";`
which returns something like:
echo... (2 Replies)
Hi ,I am trying to assign string to variable ,but it doesn't work
Also could you show me different ways to use grep,(I am trying to get the first,second and first column form file,and I am counting the chars)
let name=`grep "$id" product | cut -c6-20` (25 Replies)
Hi, wondering if it's been asked before but didn't find matches from google. Basically I have this line:
myvar=$(echo -e "a\tb")
Now somehow the '\t' from the echo output gets replaced with white space and then stored in $myvar.
It creates a problem for me later to use tab as delimiter to do... (2 Replies)
Hello All,
Hope you're doing well !
I am trying below command to be passed in a shell script, header_date_14 is a variable and $1 is the name of a file I intend to pass as a command line argument, however command line argument is not being accepted.
header_date_14=$(m_dump... (8 Replies)
In the else of the main if condition .
else
set lnk = $(readlink -f <path> | cut -d '/' -f7)
echo "$lnk"
if ]
When I run the above on command line , the execution seems to be fine and I get the desired output. But when I try to assign it to a variable within a loop... (12 Replies)
Hi,
I have the script below. When i assign SSH_COMMAND to "ssh -o ConnectTimeout=2 ${SERVER} ${AS_SUDO} ${COMMANDS}" and then execute it as ${SSH_COMMAND} I get the following error:
ssh: Could not resolve hostname sudo: Name or service not known
ssh: Could not resolve hostname sudo: Name or... (3 Replies)
Hi,
I am attempting to assign the output of the following command, to two bash variables, var1 and var2 using "read," but it doesn't seem to be working.
# openstack hypervisor stats show | awk -F'|' 'NR==14{print $2,$3}'
vcpus 92
# echo $?
0
# openstack hypervisor... (4 Replies)
Discussion started by: sand1234
4 Replies
LEARN ABOUT REDHAT
open
OPEN(1) Linux 1.x OPEN(1)NAME
open - start a program on a new virtual terminal (VT).
SYNOPSIS
open [-c vtnumber] [-s] [-u] [-l] [-v] [--] command command_options
DESCRIPTION
open will find the first available VT, and run on it the given command with the given command options, standard input, output and error are
directed to that terminal. The current search path ($PATH) is used to find the requested command. If no command is specified then the envi-
ronment variable $SHELL is used.
OPTIONS
-c vtnumber
Use the given VT number and not the first available. Note you must have write access to the supplied VT for this to work.
-s Switch to the new VT when starting the command. The VT of the new command will be made the new current VT.
-u Figure out the owner of the current VT, and run login as that user. Suitable to be called by init. Shouldn't be used with -c or -l.
-l Make the command a login shell. A - is prepended to the name of the command to be executed.
-v Be a bit more verbose.
-w wait for command to complete. If -w and -s are used together then open will switch back to the controlling terminal when the command
completes.
-- end of options to open.
NOTE
If open is compiled with a POSIX (Gnu) getopt() and you wish to set options to the command to be run, then you must supply the end of
options -- flag before the command.
EXAMPLES
open can be used to start a shell on the next free VT, by using the command:
open bash
To start the shell as a login shell, use:
open -l bash
To get a long listing you must supply the -- separator:
open -- ls -l
SEE ALSO login(1), doshell(8), switchto(1).
AUTHOR
Jon Tombs <jon@gtex02.us.es or jon@robots.ox.ac.uk>
-w idea from "sam".
19 Jul 1996 V1.4 OPEN(1)