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Full Discussion: Substituting variable value in AWK /start/,/stop/
Top Forums Shell Programming and Scripting Substituting variable value in AWK /start/,/stop/ Post 302307693 by whomi on Thursday 16th of April 2009 05:33:08 AM
Old 04-16-2009
10x 4 reply...
bt still its not working..
I think u ddnt undersand my requirement.

Here i want to retrieve the value based on the YESTERDAYS Date and TODAYS date and my script will redirect the content of the file Between yesterdays date and todays date. The file on which i am taking the search is having the daily update mentioning the date format e.g say Apr 16 ,Apr 15,Apr 14 like that. so if i pass the value Apr 15 in place of YESTERDAY variable and Apr 16 for TODAYS then it has to give the content of the file between these two dates.

i am using awk command of search string '/START/,/STOP/' where START if 4 YESTERDAY and STOP 4 TODAY... and the syntax which awk command use for this kind of search is shown above in colored..
So here i have already defined the variable YESTERDAY and TODAY...
My problem is how to pass the value for both the variable.....

My code is some what like this

Code:
YESTERDAY=`TZ=aaa24 date +"%b %d"`
TODAY=`date +"%b %d"`
echo $TODAY
echo $YESTERDAY
awk '/"$YESTERDAY {print}"/,/"$TODAY {print}"/' $HOME/alert_out.log >> $HOME/alert_work.log
 
but here its not passing the value 4 both variables though its still creating the file $HOME/alert_work.log but with zeor content.

 

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set_color

set_color(1)							       fish							      set_color(1)

NAME

       set_color - set_color - set the terminal color

set_color - set the terminal color
   Synopsis
       set_color [-v --version] [-h --help] [-b --background COLOR] [COLOR]

   Description
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       o -b, --background Set the background color

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