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Full Discussion: Executing a Java Program
Top Forums Shell Programming and Scripting Executing a Java Program Post 302307618 by cbkihong on Wednesday 15th of April 2009 11:59:44 PM
Old 04-16-2009
(1) You do not need the .java to run. Only the .class files will do.

(2) You do not run Java apps like that.

You set the classpath (using the -cp option) to point to the directory where you put your .class files.

Or you "cd" in your script to that directory before you call java. That may probably eliminate the need for -cp in simpler cases.

If your class containing the main() method is Apple, put in /root/test, then the command is simply like

java -cp /root/test:. Apple

or if the current working directory is /root/test this is just

java Apple
 

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schemagen(1)						      General Commands Manual						      schemagen(1)

NAME
schemagen - Java(TM) Architecture for XML Binding Schema Generator Specification Version: 2.0 Reference Implementation (RI) Version: 2.0 ea3 Launching schemagen The schema generator can be launched using the appropriate schemagen shell script in the bin directory for your platform. The current schema generator can process either Java source files or class files. We also provide an Ant task to run the schema generator - see the instructions for using schemagen with Ant. For Solaris/Linux % path/to/jaxb/bin/schemagen.sh Foo.java Bar.java ... Note: Writing schema1.xsd For WindowsNT/2000/XP > path ojaxbinschemagen.bat Foo.java Bar.java ... Note: Writing schema1.xsd If your java sources/classes reference other classes, they must be accessable on your system CLASSPATH environment variable, or they need to be given to the tool by using the -classpath/-cp options. Otherwise you will see errors when generating your schema. Command Line Options Usage: schemagen [-options ...] <java files> Options: -d <path> : Specify where to place processor and javac generated class files -cp <path> : Specify where to find user specified files -classpath <path> : Specify where to find user specified files -help : Display this usage message Generated Resource Files The current schema generator simply creates a schema file for each namespace referenced in your Java classes. There is no way to control the name of the generated schema files at this time. For that purpose, use the schema generator ant task. See Also o JAXB 2.0: * Release Notes @ http://java.sun.com/webservices/docs/2.0/jaxb/ReleaseNotes.html * XJC @ http://java.sun.com/webservices/docs/2.0/jaxb/xjc.html * XJCTask @ http://java.sun.com/webservices/docs/2.0/jaxb/xjcTask.html * SchemaGen @ http://java.sun.com/webservices/docs/2.0/jaxb/schemagen.html * schemagenTask @ http://java.sun.com/webservices/docs/2.0/jaxb/schemagenTask.html * Sample Apps @ http://java.sun.com/webservices/docs/2.0/jaxb/samples.html * Changelog @ http://java.sun.com/webservices/docs/2.0/jaxb/changelog2.html o JAXB 1.0.x: * Release Notes @ http://java.sun.com/webservices/docs/2.0/jaxb/jaxb-1_0.html * Changelog @ http://java.sun.com/webservices/docs/2.0/jaxb/changelog.html o JAXB RI Extensions: * Runtime Properties @ http://java.sun.com/webservices/docs/2.0/jaxb/vendorProperties.html * XJC Customizations @ http://java.sun.com/webservices/docs/2.0/jaxb/vendorCustomizations.html * Develop Plugins @ http://java.sun.com/webservices/docs/2.0/jaxb/developPlugins.html o JAXB RI Schema Languages: * W3C XML Schema @ http://java.sun.com/webservices/docs/2.0/jaxb/vendorSchemaLangs.html#xschema * RELAX NG @ http://java.sun.com/webservices/docs/2.0/jaxb/vendorSchemaLangs.html#relaxng * DTD @ http://java.sun.com/webservices/docs/2.0/jaxb/vendorSchemaLangs.html#dtd o JAXB Community: * Java.net Homepage @ http://jaxb.dev.java.net * Developer interest list @ https://jaxb.dev.java.net/servlets/ProjectMailingListList * FAQ @ https://jaxb.dev.java.net/faq/index.html 07 Aug 2006 schemagen(1)
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