Dear unix gurus,
I have a data file with header information about a subject and also 3 columns of n rows of data on various items he owns. The data file looks something like this:
adam peter
blah blah blah
blah blah blah
car
01 30 200
02 31 400
03 57 121
.. .. ..
.. .. ..
n y... (8 Replies)
Hi all,
I want to read some specific rows & columns in the .xls file with my script to get the data to be manipulated. Now, I can read the .xls file correctly & i can go to the specific sheet that I want but i have a problem to specify the specific rows & columns. I mean, I want to get the info... (0 Replies)
Hi Friends,
I have come across some files where some of the columns don not have data.
Key, Data1,Data2,Data3,Data4,Data5
A,5,6,,10,,
A,3,4,,3,,
B,1,,4,5,,
B,2,,3,4,,
If we see the above data on Data5 column do not have any row got filled. So remove only that column(Here Data5) and... (4 Replies)
Hi all, I know this sounds suspiciously like a homework course; but, it is not.
My goal is to take a file, and match my "ID" column to the "Date" column, if those conditions are true, add the total number of minutes worked and place it in this file, while not printing the original rows that I... (6 Replies)
Hi all, I'm pretty much a newbie to UNIX. I would appreciate any help with UNIX coding on comparing two large csv files (greater than 10 GB in size), and output a file with matching columns.
I want to compare file1 and file2 by 'id' and 'chain' columns, then extract exact matching rows'... (5 Replies)
Hi, I am trying to selectively merge two files based on keys reported in the 1st column.
File1:
#file1-header1
file1-header2
111 qwe rtz uio
198 asd fgh jkl
165 yxc
789 poi uzt rew
89 lkj
File2:
#file2-header2
file2-header2
165 ghz nko2 ... (2 Replies)
trying to sort an array, only the 4th column is uniq,
have this:
dog cat bird house1
dog cat bird house2
dog cat bird house3
rose daisy tulip house1
rose daisy tulip house3
would like this:
dog cat bird house1 house2 house3
rose daisy tulip house1 missing house3
any help... (6 Replies)
Discussion started by: jimmyf
6 Replies
LEARN ABOUT REDHAT
dspsv
DSPSV(l) ) DSPSV(l)
NAME
DSPSV - compute the solution to a real system of linear equations A * X = B,
SYNOPSIS
SUBROUTINE DSPSV( UPLO, N, NRHS, AP, IPIV, B, LDB, INFO )
CHARACTER UPLO
INTEGER INFO, LDB, N, NRHS
INTEGER IPIV( * )
DOUBLE PRECISION AP( * ), B( LDB, * )
PURPOSE
DSPSV computes the solution to a real system of linear equations A * X = B, where A is an N-by-N symmetric matrix stored in packed format
and X and B are N-by-NRHS matrices.
The diagonal pivoting method is used to factor A as
A = U * D * U**T, if UPLO = 'U', or
A = L * D * L**T, if UPLO = 'L',
where U (or L) is a product of permutation and unit upper (lower) triangular matrices, D is symmetric and block diagonal with 1-by-1 and
2-by-2 diagonal blocks. The factored form of A is then used to solve the system of equations A * X = B.
ARGUMENTS
UPLO (input) CHARACTER*1
= 'U': Upper triangle of A is stored;
= 'L': Lower triangle of A is stored.
N (input) INTEGER
The number of linear equations, i.e., the order of the matrix A. N >= 0.
NRHS (input) INTEGER
The number of right hand sides, i.e., the number of columns of the matrix B. NRHS >= 0.
AP (input/output) DOUBLE PRECISION array, dimension (N*(N+1)/2)
On entry, the upper or lower triangle of the symmetric matrix A, packed columnwise in a linear array. The j-th column of A is
stored in the array AP as follows: if UPLO = 'U', AP(i + (j-1)*j/2) = A(i,j) for 1<=i<=j; if UPLO = 'L', AP(i + (j-1)*(2n-j)/2) =
A(i,j) for j<=i<=n. See below for further details.
On exit, the block diagonal matrix D and the multipliers used to obtain the factor U or L from the factorization A = U*D*U**T or A
= L*D*L**T as computed by DSPTRF, stored as a packed triangular matrix in the same storage format as A.
IPIV (output) INTEGER array, dimension (N)
Details of the interchanges and the block structure of D, as determined by DSPTRF. If IPIV(k) > 0, then rows and columns k and
IPIV(k) were interchanged, and D(k,k) is a 1-by-1 diagonal block. If UPLO = 'U' and IPIV(k) = IPIV(k-1) < 0, then rows and columns
k-1 and -IPIV(k) were interchanged and D(k-1:k,k-1:k) is a 2-by-2 diagonal block. If UPLO = 'L' and IPIV(k) = IPIV(k+1) < 0, then
rows and columns k+1 and -IPIV(k) were interchanged and D(k:k+1,k:k+1) is a 2-by-2 diagonal block.
B (input/output) DOUBLE PRECISION array, dimension (LDB,NRHS)
On entry, the N-by-NRHS right hand side matrix B. On exit, if INFO = 0, the N-by-NRHS solution matrix X.
LDB (input) INTEGER
The leading dimension of the array B. LDB >= max(1,N).
INFO (output) INTEGER
= 0: successful exit
< 0: if INFO = -i, the i-th argument had an illegal value
> 0: if INFO = i, D(i,i) is exactly zero. The factorization has been completed, but the block diagonal matrix D is exactly singu-
lar, so the solution could not be computed.
FURTHER DETAILS
The packed storage scheme is illustrated by the following example when N = 4, UPLO = 'U':
Two-dimensional storage of the symmetric matrix A:
a11 a12 a13 a14
a22 a23 a24
a33 a34 (aij = aji)
a44
Packed storage of the upper triangle of A:
AP = [ a11, a12, a22, a13, a23, a33, a14, a24, a34, a44 ]
LAPACK version 3.0 15 June 2000 DSPSV(l)