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Top Forums Shell Programming and Scripting Piping STDOUT as pattern to grep or sed Post 302305535 by VNR on Thursday 9th of April 2009 07:23:45 AM
Old 04-09-2009
Piping STDOUT as pattern to grep or sed

$>cat file.txt
123 d3
234 abc 3
zyf 23
124 def 8
ghi kz0
...
...

I have the following output on the screen through <some command>.
$> <some command>
abc
def
ghi
...
...

I have to search for each of these patterns in the file.txt and print the lines in file.txt matching the output of <some command>.

I have tried to pipe it to grep like this
$> <some command> | xargs grep file.txt
But grep takes the pipe output as file and not as pattern.

Is there any way the output on STDOUT can be piped as pattern to grep or sed or awk without using a perl script.

Thanks & Regards
VNR
 

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ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD
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