Sponsored Content
Full Discussion: Getting part of a string
Top Forums Shell Programming and Scripting Getting part of a string Post 302305211 by Amit.Sagpariya on Wednesday 8th of April 2009 08:58:24 AM
Old 04-08-2009
Hi raghu,

Here is the ans....

Quote:
$ LOCATION=`dirname $FILE`
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

how to get the last part of a string followed by a pattern

assuming "cat" is the pattern, string (regardless length) asdadfcat4 I need to get 4 for eirtrjkkkcat678- I'd get 678 (in b-shell) Thanks in advance!!! (4 Replies)
Discussion started by: bluemoon1
4 Replies

2. Shell Programming and Scripting

Need help regarding replacing a part of string

Hi all suppose i have a string "abacus sabre", i need to replace occurences 'ab' with 'cd' and i need to store this result into same string and i need to return this result from script to the calling function, where as the string is passed from calling function. i tried like this ... (1 Reply)
Discussion started by: veerapureddy
1 Replies

3. UNIX for Dummies Questions & Answers

Printing a part of a string

hi I have the input as follows ABC =893 JKL = "jee" alias PQR = 9833 alias STUVE = "kuiue" I should be able to print as follows ABC JKL alias PQR alias STUVE Thanks Suresh (7 Replies)
Discussion started by: ssuresh1999
7 Replies

4. UNIX for Dummies Questions & Answers

excise a part of string

Dear all, will appreciate your help with this (supposedly simple) thing. How to use sed to replace a part of string like this: (TAGthenwhatever: into (TAG: meaning that '(TAG' (known, can be specified to sed and is marked with the '(' at the beginning) will stay and the 'thenwhatever'... (9 Replies)
Discussion started by: roussine
9 Replies

5. Shell Programming and Scripting

Delete part of string

This command: du -s /Applications/TextMate.app Returns an output like this: 65792 /Applications/TextMate.app I need to delete the space and the file path in the output leaving just the number. Thanks (2 Replies)
Discussion started by: pcwiz
2 Replies

6. Shell Programming and Scripting

Part of a string

Hi mates, I am doing a script in ksh. I have the following string: /opt/one/two/four/five/myFile.txt And I have a variable: echo "${variable}" -> /opt/one/two/ I would like to have just the string: four/five/myFile.txt What is the better way to do that? Thanks in... (3 Replies)
Discussion started by: gonzaloron
3 Replies

7. Shell Programming and Scripting

Need to take one part from a string

I have a string something like "/opt/src/default.cfg" OR /opt/src/common/one This whole string stored in an array. The problem is this string is not constant and it will keep on changing as lot of strings are stored in the array and it will be look like :- case 1 /opt/src/default.cfg ... (8 Replies)
Discussion started by: Renjesh
8 Replies

8. UNIX for Dummies Questions & Answers

Print part of string

I have a file called file.txt It contains strings: ALT=someone@acme.com TO=whoever@lalalulu.com How could find and print the actual address after the = sign for any given instance? I need the command to print one of them - for example someone@acme.com But have in mind that this... (3 Replies)
Discussion started by: svetoslav_sj
3 Replies

9. Shell Programming and Scripting

Deleting part of a string : string manipulation

i have something like this... echo "teCertificateId" | awk -F'Id' '{ print $1 }' | awk -F'te' '{ print $2 }' Certifica the awk should remove 'te' only if it is present at the start of the string.. anywhere else it should ignore it. expected output is Certificate (7 Replies)
Discussion started by: vivek d r
7 Replies

10. Shell Programming and Scripting

Extracting a part of a string

Hi, I needed to extract some specific characters from a string based on user input. For example: After the script executes the user enters the following details: Please enter the string: This is a shell script Please enter the starting position: 11 Please enter the number of characters to be... (4 Replies)
Discussion started by: ChandanN
4 Replies
SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
All times are GMT -4. The time now is 03:04 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy