I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
How to convert the date field from dd/mm/yyyy to yyyy/mm/dd in unix
my script will generate text file which have two fields
one is date and another is name of the server for example this is sample date which I have to sort based on older to newer date the problem is when I found out sort will... (4 Replies)
Hi all
I have some pipe-separated data in the form:
5/12/2008 00:00:00|31/1/2009 00:00:00|SOMESTUFF|OTHERSTUFF
12/31/2008 00:00:00|15/1/2009 00:00:00|MORESTUFF|REMAININGSTUFF
1/1/1023 00:00:00|16/5/2047 00:00:00|THEREST|YETMORE
I need to zero-pad the single-digit days and months, using... (3 Replies)
My csv has data like this
x,x,3452,2/18/1986,abc
x,g,19711,1/24/1986,abc
i want to replace date in the following format YYYY-mm-dd
how do i convert using awk script ? (8 Replies)
(Attention: Green PHP newbie !)
I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Hello,
I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10)
To extract the dates, I am using shell substrings, i.e.:
read line
... (4 Replies)
I've seen a lot of posts on this and have tried the following:
echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";'
But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY.
I am using bash and don't know... (4 Replies)
I am using bash that when run downloads a file a verifies that there is data in it. What I am not able to do is have a user enter a date in any format they wish and have it converted to m-d-yyyy. Thank you :).
Bash
printf " Welcome to NGS analysis, checking for new files and creating a... (2 Replies)
I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY.
When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD
file... (3 Replies)
How to convert mmm-yy to mm/dd/yyyy format in unix ?
example:
Jan-99 to 01/01/1999
Jan-00 to 01/01/2000
Jan-25 to 01/01/2025
Dec-99 to 01/12/1999
Dec-00 to 01/12/2000
Dec-25 to 01/12/2025
YY anything between 00-50 should be 2000-2050
YY anything between 51-99 should be 1951-1999
... (2 Replies)
Discussion started by: gksenthilkumar
2 Replies
LEARN ABOUT DEBIAN
apr::uuid
libapache2-mod-perl2-2.0.7::docs::api::APR::UUID(3pm) User Contributed Perl Documentation libapache2-mod-perl2-2.0.7::docs::api::APR::UUID(3pm)NAME
APR::UUID - Perl API for manipulating APR UUIDs
Synopsis
use APR::UUID ();
# get a random UUID and format it as a string
my $uuid = APR::UUID->new->format;
# $uuid = e.g. 'd48889bb-d11d-b211-8567-ec81968c93c6';
# same as the object returned by APR::UUID->new
my $uuid_parsed = APR::UUID->parse($uuid);
Description
"APR::UUID" is used to get and manipulate random UUIDs.
It allows you to "create" random UUIDs, which when "formatted" returns a string like:
'd48889bb-d11d-b211-8567-ec81968c93c6';
which can be parsed back into the "APR::UUID" object with "parse()".
API
"APR::UUID" provides the following functions and/or methods:
"format"
Convert an "APR::UUID object" object into a string presentation:
my $uuid_str = $uuid->format;
obj: $uuid ( "APR::UUID object" )
ret: $uuid_str
returns a string representation of the object (.e.g 'd48889bb-d11d-b211-8567-ec81968c93c6').
since: 2.0.00
"new"
Create a "APR::UUID object" using the random engine:
my $uuid = APR::UUID->new;
class: "APR::UUID" ( "APR::UUID class" )
ret: $uuid ( "APR::UUID object" )
since: 2.0.00
"DESTROY"
$uuid->DESTROY;
obj: "APR::UUID" ( "APR::UUID object" )
ret: no return value
since: 2.0.00
Do not call this method, it's designed to be only called by Perl when the variable goes out of scope. If you call it yourself you will get
a segfault when perl will call DESTROY on its own.
"parse"
Convert a UUID string into an "APR::UUID object" object:
$uuid = APR::UUID->parse($uuid_str)
arg1: $uuid_str (string)
UUID string (.e.g 'd48889bb-d11d-b211-8567-ec81968c93c6')
ret: $uuid ( "APR::UUID object" )
The new object.
since: 2.0.00
See Also
mod_perl 2.0 documentation.
Copyright
mod_perl 2.0 and its core modules are copyrighted under The Apache Software License, Version 2.0.
Authors
The mod_perl development team and numerous contributors.
perl v5.14.2 2011-02-08 libapache2-mod-perl2-2.0.7::docs::api::APR::UUID(3pm)