04-02-2009
Hi All,
Thank you very much for your explaination.
@marcus121 : This is pretty clear now. just one point..
Quote:
awk -F, '{printf("%i,%s,%s,%i,%i\n",$1,$2,$3,$4,$5)}' filename | grep -v '0,,0,0,0,,'
It is clear that above will print only 5 fields ( exclude TESTING
i.e
Quote:
88562848,21-JAN-08,2741079, -1188,-7433,TESTING
88558314,21-JAN-08,2741189, -1273,-7976,TESTING
now grep -v '0,,0,0,0,,' , I guess pointing to -
1 st field - 0
2nd - null
3rd, 4th, 5th - 0
6 th - null ..
but in the resulting file, there will be no 6th field (TESTING) !!. then for what purpose, the last 2 commas are there in grep?
also, regarding the comma in 5th and 6th field in the new file..
my requirement is..
instead of 2,25 i want to print (2*100)+25 i.e 225
in general, 4th and 5th field, i want the below value
(value_before_comma*100)+value_after_comma
though I am working on it.. trying like $4*=100 but I am having problem in splitting both values for doing different calulation
I appreciate if i can get some clue.
Thanks.
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ZGREP(1) General Commands Manual ZGREP(1)
NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)
ZGREP(1)