Sponsored Content
Top Forums Shell Programming and Scripting Getting value from a variable Post 302303149 by cfajohnson on Thursday 2nd of April 2009 02:14:49 AM
Old 04-02-2009
Code:
eval "DSTDIR=\$BKUP_$DIR"

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

ksh: A part of variable A's name is inside of variable B, how to update A?

This is what I tried: vara=${varb}_count (( vara += 1 )) Thanks for help (4 Replies)
Discussion started by: pa3be
4 Replies

2. Shell Programming and Scripting

Sed variable substitution when variable constructed of a directory path

Hello, i have another sed question.. I'm trying to do variable substition with sed and i'm running into a problem. my var1 is a string constructed like this: filename1 filerev1 filepath1 my var2 is another string constructed like this: filename2 filerev2 filepath2 when i do... (2 Replies)
Discussion started by: alrinno
2 Replies

3. Shell Programming and Scripting

Insert a line including Variable & Carriage Return / sed command as Variable

I want to instert Category:XXXXX into the 2. line something like this should work, but I have somewhere the wrong sytanx. something with the linebreak goes wrong: sed "2i\\${n}Category:$cat\n" Sample: Titel Blahh Blahh abllk sdhsd sjdhf Blahh Blah Blahh Blahh Should look like... (2 Replies)
Discussion started by: lowmaster
2 Replies

4. Shell Programming and Scripting

How to define a variable with variable definition is stored in a variable?

Hi all, I have a variable say var1 (output from somewhere, which I can't change)which store something like this: echo $var1 name=fred age=25 address="123 abc" password=pass1234 how can I make the variable $name, $age, $address and $password contain the info? I mean do this in a... (1 Reply)
Discussion started by: freddy1228
1 Replies

5. Shell Programming and Scripting

Split variable length and variable format CSV file

Dear all, I have basic knowledge of Unix script and her I am trying to process variable length and variable format CSV file. The file length will depend on the numbers of Earnings/Deductions/Direct Deposits. And The format will depend on whether it is Earnings/Deductions or Direct Deposits... (2 Replies)
Discussion started by: chechun
2 Replies

6. Shell Programming and Scripting

Not able to store command inside a shell variable, and run the variable

Hi, I am trying to do the following thing var='date' $var Above command substitutes date for and in turn runs the date command and i am getting the todays date value. I am trying to do the same thing as following, but facing some problems, unique_host_pro="sed -e ' /#/d'... (3 Replies)
Discussion started by: gvinayagam
3 Replies

7. Shell Programming and Scripting

Variable not found error for a variable which is returned from stored procedure

can anyone please help me with this: i have written a shell script and a stored procedure which has one OUT parameter. now i want to use that out parameter as an input to the unix script but i am getting an error as variable not found. below are the unix scripts and stored procedure... ... (4 Replies)
Discussion started by: swap21783
4 Replies

8. Red Hat

How to pass value of pwd as variable in SED to replace variable in a script file

Hi all, Hereby wish to have your advise for below: Main concept is I intend to get current directory of my script file. This script file will be copied to /etc/init.d. A string in this copy will be replaced with current directory value. Below is original script file: ... (6 Replies)
Discussion started by: cielle
6 Replies

9. Shell Programming and Scripting

[Solved] How to increment and add variable length numbers to a variable in a loop?

Hi All, I have a file which has hundred of records with fixed number of fields. In each record there is set of 8 characters which represent the duration of that activity. I want to sum up the duration present in all the records for a report. The problem is the duration changes per record so I... (5 Replies)
Discussion started by: danish0909
5 Replies

10. UNIX for Advanced & Expert Users

Passing variable as input & storing output in other variable

I have a below syntax its working fine... var12=$(ps -ef | grep apache | awk '{print $2,$4}') Im getting expected output as below: printf "%b\n" "${VAR12}" dell 123 dell 456 dell 457 Now I wrote a while loop.. the output of VAR12 should be passed as input parameters to while loop and results... (5 Replies)
Discussion started by: sam@sam
5 Replies
RUSHWHO(1)							      Gnurush								RUSHWHO(1)

NAME
rushwho - show users logged in using GNU rush SYNOPSIS
rushwho [-F STRING] [-f DIR] [-H] rushwho {-v | -h | --usage} DESCRIPTION
Print various pieces of information about all users presently using the restricted remote shell rush. OPTIONS
-F STRING | --format=STRING Use specified format string instead of the default string. -f DIR | --file=DIR Use database directory DIR. Default location is /var/lib/rush. -H | --no-header Suppress header line in printout. -v | --version Display program version. -h | --help Display a short help message. --usage Display a concise usage summary. SEE ALSO
The full documentation for rushwho is maintained as a Texinfo manual. If the info and rush programs are properly installed at your site, the command info rush should give you access to the complete manual. See also rush(8) and rushlast(1). AUTHOR
This text was written by Mats Erik Andersson for the Debian project, since the original source supplies a documentation only in the form of a GNU Texinfo manual. GNU Rush 1.7 December 2010 RUSHWHO(1)
All times are GMT -4. The time now is 12:54 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy