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Top Forums UNIX for Dummies Questions & Answers Replacing a character in a line Post 302303131 by Usha Shastri on Thursday 2nd of April 2009 12:59:33 AM
Old 04-02-2009
Replacing a character in a line

Hi All

I want to replace a character in a line, but position will be different form one iteration to another.
So i m keeping the position i a variable.
I am trying with following code

Code:
pos=3
echo "Hello World, Good Morning" | sed 's/\(.\{$pos\}\)./\1Y/'

But its not working, Can you please help.

Thanks

Last edited by Yogesh Sawant; 04-02-2009 at 02:41 AM.. Reason: added code tags
 

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mdraw_default_line_break(3m17n) 				 The m17n Library				   mdraw_default_line_break(3m17n)

NAME
mdraw_default_line_break - Calculate a line breaking position. SYNOPSIS
int mdraw_default_line_break (MText * mt, int pos, int from, int to, int line, int y) DESCRIPTION
Calculate a line breaking position. The function mdraw_default_line_break() calculates a line breaking position based on the line number line and the coordinate y, when a line is too long to fit within the width limit. pos is the position of the character next to the last one that fits within the limit. from is the position of the first character of the line, and to is the position of the last character displayed on the line if there were not width limit. line and y are reset to 0 when a line is broken by a newline character, and incremented each time when a long line is broken because of the width limit. RETURN VALUE
This function returns a character position to break the line. COPYRIGHT
Copyright (C) 2001 Information-technology Promotion Agency (IPA) Copyright (C) 2001-2011 National Institute of Advanced Industrial Science and Technology (AIST) Permission is granted to copy, distribute and/or modify this document under the terms of the GNU Free Documentation License <http://www.gnu.org/licenses/fdl.html>. Version 1.6.2 12 Jan 2011 mdraw_default_line_break(3m17n)
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