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Full Discussion: Replace space
Top Forums Shell Programming and Scripting Replace space Post 302302885 by Franklin52 on Wednesday 1st of April 2009 09:19:35 AM
Old 04-01-2009
This prints the lines from the 3th position (deletes the 1st 3 characters of a line):

Code:
sed 's/...//' file

With awk you can use the substr() function:

Code:
awk '{print substr($0, 3}' file

Regards
 

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PR(1)							      General Commands Manual							     PR(1)

NAME
pr - print file SYNOPSIS
pr [ option ... ] [ file ... ] DESCRIPTION
Pr produces a printed listing of one or more files on its standard output. The output is separated into pages headed by a date, the name of the file or a specified header, and the page number. With no file arguments, pr prints its standard input. Options apply to all following files but may be reset between files: -n Produce n-column output. +n Begin printing with page n. -b Balance columns on last page, in case of multi-column output. -d Double space. -en Set the tab stops for input text every n spaces. -h Take the next argument as a page header (file by default). -in Replace sequences of blanks in the output by tabs, using tab stops set every n spaces. -f Use formfeeds to separate pages. -ln Take the length of the page to be n lines instead of the default 66. -m Print all files simultaneously, each in one column. -n Number the lines of each file. -on Offset the left margin n character positions. -sc Separate columns by the single character c instead of aligning them with white space. A missing c is taken to be a tab. -t Do not print the 5-line header or the 5-line trailer normally supplied for each page. -wn For multi-column output, take the width of the page to be n characters instead of the default 72. SOURCE
/sys/src/cmd/pr.c SEE ALSO
cat(1), lp(1) PR(1)
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