03-30-2009
sizeof an array of structure without using 'sizeof' operator
Hi All,
is it possible to find out the size of an array of structures ( without using 'sizeof' operator). The condition is we have the array of structure instant but we are not aware of the elements inside the structure.
Can someone help me out?
Thanks in advance.
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LEARN ABOUT DEBIAN
std::tuple
std::tuple< _Elements >(3cxx) std::tuple< _Elements >(3cxx)
NAME
std::tuple< _Elements > -
SYNOPSIS
Inherits _Tuple_impl< 0, _Elements...>.
Public Member Functions
constexpr tuple (const _Elements &...__elements)
template<typename... _UElements, typename = typename std::enable_if<sizeof...(_UElements) ==
sizeof...(_Elements)>::type> tuple (_UElements &&...__elements)
constexpr tuple (const tuple &)
tuple (tuple &&__in)
template<typename... _UElements, typename = typename std::enable_if<sizeof...(_UElements) ==
sizeof...(_Elements)>::type> tuple (const tuple< _UElements...> &__in)
template<typename... _UElements, typename = typename std::enable_if<sizeof...(_UElements) ==
sizeof...(_Elements)>::type> tuple (tuple< _UElements...> &&__in)
tuple & operator= (const tuple &__in)
tuple & operator= (tuple &&__in)
template<typename... _UElements, typename = typename std::enable_if<sizeof...(_UElements) ==
sizeof...(_Elements)>::type> tuple & operator= (const tuple< _UElements...> &__in)
template<typename... _UElements, typename = typename std::enable_if<sizeof...(_UElements) ==
sizeof...(_Elements)>::type> tuple & operator= (tuple< _UElements...> &&__in)
void swap (tuple &__in)
Detailed Description
template<typename... _Elements>class std::tuple< _Elements >
tuple
Definition at line 230 of file tuple.
Author
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libstdc++ Tue Nov 27 2012 std::tuple< _Elements >(3cxx)