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Full Discussion: array dynamic allocation
Top Forums Programming array dynamic allocation Post 302302078 by littleboyblu on Monday 30th of March 2009 03:43:36 AM
Old 03-30-2009
thanks pshaikh
 

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DYNARR(3pub)						       C Programmer's Manual						      DYNARR(3pub)

NAME
dynarr, dynarr_init, dynarr_resize, dynarr_free - simple dynamic arrays SYNOPSIS
#include <publib.h> void dynarr_init(struct dynarr *da, size_t elsize); int dynarr_resize(struct dynarr *da, size_t newsize); void dynarr_free(struct dynarr *da); DESCRIPTION
These functions make it easier to use dynamic arrays, i.e., arrays that are allocated with malloc(3) and resized with realloc(3). Below is a typical code fragment for implementing a dynamic array that is resized as more input is read. char *p, *line; size_t alloc, len; len = 0; alloc = 1024; if ((line = malloc(alloc)) == NULL) abort(); while (fgets(line + len, alloc-len, stdin) != NULL) { len = strlen(line); alloc += 1024; if ((p = realloc(alloc)) == NULL) abort(); alloc = p; } (The error handling is intentionally simplified.) Below is the above fragment with the dynarr(3). struct dynarr da; dynarr_init(&da); while (fgets((char *)da.data + da.used, da.alloc-da.len, stdin) != NULL) { da.used = strlen(da.data); if (dynarr_resize(&da, da.alloc + 1024) == -1) abort(); } The code is a bit simpler, and all the memory allocation details and most of the error checking code is hidden away. The dynamic array is represented by a struct dynarr: struct dynarr { void *data; size_t alloc, used; }; The interface to the dynamic allocation has intentionally been made unopaque. dynarr_init initializes a struct dynarr to be an empty array, dynarr_resize sets its size to be newsize, and dynarr_free frees the array (it will become an empty array again). RETURNS
dynarr_resize returns -1 if it failed, 0 if it succeeded. It does not change the array in any way if it failed. SEE ALSO
publib(3), malloc(3), realloc(3), strdup(3) AUTHOR
Lars Wirzenius (lars.wirzenius@helsinki.fi) Publib C Programmer's Manual DYNARR(3pub)
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