Below is the snippet of the code that i have written. The damn sprintf is not working. No matter what number i enter, it is entering ceil and not floor.Any reasons why ?
Hello,
I searched a lot on this Forum.
Please help me with the below problem.
I want to divide two numbers and the result should be the next nearest whole number.
E.G. Dividing 10.8/5 ideally gives 2.16. But the result should be 3 i.e. rounded off to the next whole number.
Any help will... (2 Replies)
Hi Experts,
I have a command that gives me the output as below
root@ckpgpay11core> cat sara | awk '{ sum += $1} ; END { print sum }' | awk {'print $1/90'}
8.88889
how do i remove the decimal spaces so that the figure will round itself to 9?
Thanks. (3 Replies)
Hi,
I am trying to find if there is a way to convert regular decimal values to Paced decimal values. I tried to find a c program but I could get a Packed converted to regular decimal not the other way round.
If not unix please let me know if any other progrimming language I can use to do... (2 Replies)
Is there a way I can round time in perl to the nearest five minutes?
For example if I have log giving the following time stamps
23,52,30 it would rounded up to 23,55,00
and
23,50,01 would be rounded to 23,50,00 (3 Replies)
Hello Guys,
I'm very new on here and require some help matching up and printing some columns using awk.
I have two text files. The first file has Longitude data in column 1 (lon.txt) and the second one (node.txt) has again another Longitude data in column 1 (not exact as the first one) + in... (7 Replies)
Dear Experts,
I'm trying to find a way to round a number but in this way:
14367.577 ---> 14000
I used the following to round the number to the closer integer:
echo $var|awk '{print int($1+0.5)}'
and also:
xargs printf "%1.0f"
However, they don't work for my above... (9 Replies)
Hi all of you,
Would be great if you help me with how to round up to whole number from my input values like
2.99996,2.17890,3.00002,-2.3456,-2.7890
o/p should be like 3,2,3,-2,-3
thnks in adv!!!!
regards (3 Replies)
I have a number, which I want to convert into the nearest floating number upto two places after the decimal point.
E.g.
1.2346 will become 1.23
but
1.2356 will become 1.24 .
Similarly
0.009 will be 0.01
and
0.001 will be 0.00 or 0.0 (not 0, wnat to keep the decimal... (1 Reply)
Heyas
Trying to calculate the total size of a file by reading its bitrate.
Code snippet:
fs_expected() { #
# Returns the expected filesize in bytes
#
pr_str() {
ff=$(cat $TMP.info)
d="${ff#*bitrate: }"
echo "${d%%,*}" | $AWK '{print $1}' | head -n 1
}
t_BYTERATE=$((... (9 Replies)
Discussion started by: sea
9 Replies
LEARN ABOUT ULTRIX
ffloor
floor(3m)floor(3m)Name
floor, ffloor, fabs, ceil, ceil, trunc, ftrunc, fmod, rint - floor, absolute value, ceiling, truncation, floating point remainder and
round-to-nearest functions
Syntax
#include <math.h>
double floor(x)
double x;
float ffloor(x)
float x;
double ceil(x)
double x;
float fceil(x)
float x;
double trunc(x)
double x;
float ftrunc(x)
float x;
double fabs(x)
double x;
double fmod (x, y)
double x, y;
double rint(x)
double x;
Description
The and routines return the largest integer which is not greater than x for double and float data types, respectively.
The and routines return the smallest integer which is not less than x for double and float data types, respectively.
The and routines return the integer (represented as a floating-point number) of x with the fractional bits truncated for double and float
data types respectively.
The routine returns the absolute value |x|.
The routine returns the floating point remainder of the division of x by y: zero if y is zero or if x/y would overflow; otherwise the num-
ber f with the same sign as x, such that x = iy + f for some integer i, and |f| < |y|.
The routine returns the integer (represented as a double precision number) nearest x in the direction of the prevailing rounding mode.
In the default rounding mode, to nearest, is the integer nearest x with the additional stipulation that if |rint(x)-x|=1/2 then is even.
Other rounding modes can make act like or or round towards zero.
Another way to obtain an integer near x is to declare (in C)
double x; int k; k = x;
The C compiler rounds x towards 0 to get the integer k. Also note that, if x is larger than k can accommodate, the value of k and the
presence or absence of an integer overflow are hard to predict.
The routine is in libc.a rather than libm.a.
See Alsoabs(3), ieee(3m), math(3m)
RISC floor(3m)