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Top Forums Shell Programming and Scripting Search for a pattern in a file and print previous lines from a particular point Post 302301788 by umaislearning on Saturday 28th of March 2009 10:20:42 AM
Old 03-28-2009
Quote:
Originally Posted by Ikon
Something like this??
Code:
root@jeepanywhere /usr/src # cat test.log
1
2
3
4
5
1
2
3
4
5
1
2
3
4
5
root@jeepanywhere /usr/src # sed -n '/^2/,/^4/{/LABEL$/!p}' test.log
2
3
4
2
3
4
2
3
4

I am not able to understand this command very clearly, but this is wat I want, please tell me if that sed command will give me the below output:

suppose I have a file like the one below:

start of file-----
***********
1
2
3
4
5
========
***********
6
7
8
9
========
end of file-----
Now for eg I need to search for 8, then search for the first occurance of the pattern ***** thats jus few lines(no. of lines not fixed) above 8...then from there I need to print till end of file....
so my output needs to be something like this:
***********
6
7
8
9
============
end of file-----

Thanks in advance...
 

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QSTAIL(1)							  qstail man page							 QSTAIL(1)

NAME
qstail - Utility prints the end of a log file starting at the specified pattern. SYNOPSIS
qstail -i <path> -p <pattern> DESCRIPTION
qstail shows the end of a log file beginning with the line containing the specified pattern. This may be used to show all lines which has been written after a certain event (e.g., server restart) or time stamp. OPTIONS
-i <path> Input file to read the data from. -p <pattern> Search pattern (literal string). SEE ALSO
qsexec(1), qsfilter2(1), qsgeo(1), qsgrep(1), qslog(1), qslogger(1), qspng(1), qsrotate(1), qssign(1) AUTHOR
Pascal Buchbinder, http://opensource.adnovum.ch/mod_qos/ mod_qos utilities 10.8 June 2012 QSTAIL(1)
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