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Full Discussion: While loop error: Unexpected token done
Top Forums Shell Programming and Scripting While loop error: Unexpected token done Post 302301026 by warlock129 on Wednesday 25th of March 2009 03:50:43 PM
Old 03-25-2009
While loop error: Unexpected token done
I have tried to implement a while loop into the code but upon running the following code i am getting the errors:

./Assigntest: line 42: syntax error near unexpected token `done'
./Assigntest: line 42: `done'



The code is as follows:

Code:
#!/bin/bash
#Filename: Assignment Author: Luke Francis
quit=n
while [ "$quit" = "n" ]
do
clear
echo "OPERATOR ADMINISTRATIVE TOOL"
echo "Please enter your password:"
read password
if [ $password -eq 0600519 ]
then
clear
echo "1. User Information"
echo "2. Network Connectivity"
echo "3. Processes"
echo "4. System Information"
echo "5. Hardware Utilization"
echo "Which option do you require?"
read menunumber
case $menunumber in
1) echo "USER INFORMATION"
echo "1. Registered Users"
echo "2. Disk Usage"
echo "3. Last Logins"
echo "Q.Quit"
echo "Which option do you require?"
read menunumber2
case $menunumber2 in
1) awk -F: '{print $1}' /etc/passwd
echo "Hit the Enter Key to continue"
read junk;;
2) du
echo "Hit Enter Key to continue"
read junk;;
3) who
echo "Hit Enter Key to continue"
read junk;;
Q|q) quit=y;;
*) echo "INCORRECT PASSWORD"
"Assigntest" 43L, 925C written                                
lf1ect@star-gateway$ <0> ./Assigntest
./Assigntest: line 42: syntax error near unexpected token `done'
./Assigntest: line 42: `done'
lf1ect@star-gateway$ <2> vi Assigntest
read password
if [ $password -eq 0600519 ]
then
clear
echo "1. User Information"
echo "2. Network Connectivity"
echo "3. Processes"
echo "4. System Information"
echo "5. Hardware Utilization"
echo "Which option do you require?"
read menunumber
case $menunumber in
1) echo "USER INFORMATION"
echo "1. Registered Users"
echo "2. Disk Usage"
echo "3. Last Logins"
echo "Q.Quit"
echo "Which option do you require?"
read menunumber2
case $menunumber2 in
1) awk -F: '{print $1}' /etc/passwd
echo "Hit the Enter Key to continue"
read junk;;
2) du
echo "Hit Enter Key to continue"
read junk;;
3) who
echo "Hit Enter Key to continue"
read junk;;
Q|q) quit=y;;
*) echo "INCORRECT PASSWORD"
sleep 1
esac
done
echo "Thank you for using the Operator Administrative Tool."

To me the done statement looks to be correct but obviuosly there is something wrong i'd be grateful for some help.
Last edited by vgersh99; 03-25-2009 at 04:58 PM..
 

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shtool-echo

SHTOOL-ECHO.TMP(1)					      GNU Portable Shell Tool						SHTOOL-ECHO.TMP(1)

NAME

       shtool-echo - GNU shtool echo(1) extensional command

SYNOPSIS

       shtool echo [-n|--newline] [-e|--expand] string

DESCRIPTION

       shtool echo is an echo(1) style command which prints string to stdout and optionally provides special expansion constructs (terminal bold
       mode, environment details, date, etc) and newline control. The trick of this command is that it provides a portable -n option and hides the
       gory details needed to find out the environment details under option -e.

OPTIONS

       The following command line options are available.

       -n, --newline
	   By default, output is written to stdout followed by a "newline" (ASCII character 0x0a). If option -n is used, this newline character is
	   omitted.

       -e, --expand
	   If option -e is used, string can contain special "%x" constructs which are expanded before the output is written. Currently the
	   following constructs are recognized:

	   %B  switch terminal mode to bold display mode.

	   %b  switch terminal mode back to normal display mode.

	   %u  the current user name.

	   %U  the current user id (numerical).

	   %g  the current group name.

	   %G  the current group id (numerical).

	   %h  the current hostname (without any domain extension).

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EXAMPLE

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HISTORY

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SEE ALSO

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