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Top Forums Shell Programming and Scripting SUPER simple bash script to repeat a command... Post 302299976 by rubionis on Sunday 22nd of March 2009 06:34:06 PM
Old 03-22-2009
A quick way would be using an infinite loop ...

Code:
#!/bin/bash

while :
 
 do

   igal -a -r -U -w 6

   sleep 30

 done

 

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IO::Async::Signal(3pm)					User Contributed Perl Documentation				    IO::Async::Signal(3pm)

NAME
"IO::Async::Signal" - event callback on receipt of a POSIX signal SYNOPSIS
use IO::Async::Signal; use IO::Async::Loop; my $loop = IO::Async::Loop->new; my $signal = IO::Async::Signal->new( name => "HUP", on_receipt => sub { print "I caught SIGHUP "; }, ); $loop->add( $signal ); $loop->run; DESCRIPTION
This subclass of IO::Async::Notifier invokes its callback when a particular POSIX signal is received. Multiple objects can be added to a "Loop" that all watch for the same signal. The callback functions will all be invoked, in no particular order. EVENTS
The following events are invoked, either using subclass methods or CODE references in parameters: on_receipt Invoked when the signal is received. PARAMETERS
The following named parameters may be passed to "new" or "configure": name => STRING The name of the signal to watch. This should be a bare name like "TERM". Can only be given at construction time. on_receipt => CODE CODE reference for the "on_receipt" event. Once constructed, the "Signal" will need to be added to the "Loop" before it will work. AUTHOR
Paul Evans <leonerd@leonerd.org.uk> perl v5.14.2 2012-10-24 IO::Async::Signal(3pm)
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