You dont need all the extra "echo" commands for one thing. Also, you need to use double quotes. The only time you should not use double quotes in the shell, are when yo uhave special characters that you mean to interpret literally. Such as if i want to say:
Your code:
SHOULD be:
notice how we got rid of the "echo" commands, and put everything in DOUBLE quotes....the variable, and the string you are comparing the variable to.
Hi
How do i compare two strings in shell script. Below is an example but I am not getting the desired output, plz help
if
then
echo success
fi
I am not getting the desired output if I do this. plz help (24 Replies)
Hi All,
While I am trying to run below code I Am getting the exception like
./abs.sh: line 102: syntax error near unexpected token `then'
./abs.sh: line 102: ` then'
The Code Snippet is:
if then
cat $file1 | sed -e... (8 Replies)
i have a string in a file which gets repeated number of times like below:
rpttxt("abc")
.
.
rpttxt("REP_TITLE")
rpttxt("BOS_TITLE")
.
.
.
.
and so on
using awk or grep how can i comapre the string( as the second half keeps varying) and store it in a temporary variable? I am using the... (3 Replies)
hi All
i am facing prob in comparing two strings that have two word.
below is the code snippet.
checkValidates="file validates"
file3_name="file"
if
then
echo "file" $file3_name "is validated successfully"
fi
when i run this i get the error as -bash: [: too many arguments
... (1 Reply)
Hey guys how do I compare 2 strings from the text file,
and check for duplication?
For example, I add an item call Laptop, it will record to the textfile call file.
If it detects duplicate it will say the record record exist?
file.txt contains
Laptop:Sony:1000
Phone:Apple:30
A head... (4 Replies)
Hi, So I got his code below. $year is a string of 2010,2011 etc.
I guess I want to convert $year to an integer so I can do my if statement to see if the year string is greater than 2010? Or how could I do this?
Right now I get a syntax error doing this.
if; then
do stuff
fi (2 Replies)
Hi All,
Im trying to compare the wc -l output with another set of rowcount outputs which returned from sql...
For Eg : Im storing the first outputs as below
<srccnt=`wc -l $HOME/*.csv | awk {'print $1'}`
and comparing this with the another set of outputs.
descnt=`seclect count(*)... (7 Replies)
Discussion started by: Deena1984
7 Replies
LEARN ABOUT PHP
define
DEFINE(3) 1 DEFINE(3)define - Defines a named constantSYNOPSIS
bool define (string $name, mixed $value, [bool $case_insensitive = false])
DESCRIPTION
Defines a named constant at runtime.
PARAMETERS
o $name
- The name of the constant.
o $value
- The value of the constant; only scalar and null values are allowed. As of PHP 7 it also possible to use array value. Scalar val-
ues are integer, float, string or boolean values. It is possible to define resource constants, however it is not recommended and
may cause unpredictable behavior.
o $case_insensitive
- If set to TRUE, the constant will be defined case-insensitive. The default behavior is case-sensitive; i.e. CONSTANT and Con-
stant represent different values.
Note
Case-insensitive constants are stored as lower-case.
RETURN VALUES
Returns TRUE on success or FALSE on failure.
CHANGELOG
+--------+---------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------+
| 7.0.0 | |
| | |
| | |
| | array values are allowed. |
| | |
+--------+---------------------------+
EXAMPLES
Example #1
Defining Constants
<?php
define("CONSTANT", "Hello world.");
echo CONSTANT; // outputs "Hello world."
echo Constant; // outputs "Constant" and issues a notice.
define("GREETING", "Hello you.", true);
echo GREETING; // outputs "Hello you."
echo Greeting; // outputs "Hello you."
// Works as of PHP 7
define('ANIMALS', array(
'dog',
'cat',
'bird'
));
echo ANIMALS[1]; // outputs "cat"
?>
SEE ALSO defined(3), constant(3), The section on Constants.
PHP Documentation Group DEFINE(3)