%% is used for escaping the special character %, so %%s wouldn't expect any command ant it will print the % character.
which is the command I need for converting the date in format
mm/dd/yyyy in a number (number of seconds) to be able for performing
comparations between dates (which date goes after the oter....)
For example, you can try this code
The output will be
So, as it is expected, the probhlem is that I can't capture the value 1237503600 in awk for performing my calculations.
Hi Gurus,
Iam new to Unix.
I had a requirement where i should use a file for example
Host.sh or Host.txt
Host = 555.254.45.14
username = aaaa
pwd = SSSSSS123
And this file need to be used in different scripts.
For example i have script1.sh
where i want to use the values of... (6 Replies)
only the arguments that are written to the file,
my script is (sh /u01app/wkf.sh"$start_no","$name","$Condition","$file_name") like that
when ever I run my script I need to write into a new file every time,
like wise I have upto10 files with different names.bec my $start_no and $name will... (1 Reply)
Hello,
i am using '#!/bin/bash', i want to make a loop in pl/sql, this loop takes values from a table according to some conditions, each time the loop choose 3 different variables. What i am not able to do is that during the loop i want my shell script to read this 3 variables and run a shell... (1 Reply)
Hi
i am calling a stored procedure from unix shell like this call
test_proc('0002','20100218');
the stored procedure was giving output
like this dbms_output.put_line(' processed earlier');
i want to see the output in the unix shell where i called.
Thanks
barani (6 Replies)
Hi All,
Can anybody please help me with how can i call my java program from shell and also pass parameter along with it so that the program can interpret the value/int and update the database.
Thanks in advance
Neha (1 Reply)
hi,
Could anyone tell me how to pass the output values of the PL/SQL procedure to Shell script and how to store that values in a shell script variable...
Thanks in advance... (5 Replies)
I know this topic has been dealt with previously, but the solutions I've seen don't work for me apparently.
I need to pass a variable defined in the shell to one in awk:
$ echo $var1
3
$ cat aaa
aaa 1
bbb 2
ccc 3
ddd 4
eee 5I've tried this, without success:
$ awk... (2 Replies)
I'm in the process of writng a function that consists of a case statement is there a way of calling the function and passing a value to it?
ie
function1 () {
case
opt1 do .....
opt2 do.....
esac
}
function opt1
I'm aware the syntax is not correct, but you get the general idea. (1 Reply)
Discussion started by: squrcles
1 Replies
LEARN ABOUT CENTOS
grub-render-label
GRUB-RENDER-LABEL(1) User Commands GRUB-RENDER-LABEL(1)NAME
grub-render-label - generate a .disk_label for Apple Macs.
SYNOPSIS
grub-render-label [OPTION...] [OPTIONS]
DESCRIPTION
Render Apple .disk_label.
-b, --bgcolor=COLOR
use COLOR for background
-c, --color=COLOR
use COLOR for text
-f, --font=FILE
use FILE as font (PF2).
-i, --input=FILE
read text from FILE.
-o, --output=FILE
set output filename. Default is STDOUT
-t, --text=STRING
set the label to render
-v, --verbose
print verbose messages.
-?, --help
give this help list
--usage
give a short usage message
-V, --version
print program version
Mandatory or optional arguments to long options are also mandatory or optional for any corresponding short options.
REPORTING BUGS
Report bugs to <bug-grub@gnu.org>.
SEE ALSO
The full documentation for grub-render-label is maintained as a Texinfo manual. If the info and grub-render-label programs are properly
installed at your site, the command
info grub-render-label
should give you access to the complete manual.
grub-render-label (GRUB) 2.02-2ubuntu8.3 July 2018 GRUB-RENDER-LABEL(1)