So I need to change the permissions of my user account. I can
access the root account on the server, but don't know how to
change the permissions of my user account. I was advised to
try 'userconf' to see if I am part of a group, but I dunno how that works. ANyone who knows how to see the... (3 Replies)
Hello Everyone,
if we log on to unix server how do we find that what permissions/roles and priveleges are assigned to any particular user.
Here i am not talking about the file permissions.
Thanks (1 Reply)
I have an application where in a user uploads files into a directory that has a collection of image files, as well as a text file that is read by a web script later. The script imports the text file data into a database, then copies the image files to a secure location. Ideally it should remove... (1 Reply)
Hi everyone,
There are couple of users of which i need to give 2 of the users admin rights so that they are able to run the administration commands like "zoneadm" and locale.
When logged in as root i am obviously able to do that.please suggest any way by which the other 2 user's permissions... (1 Reply)
hi
i want to display the usernames,usergroups user permissions and user home directory's with in a single command.and possibities are their for getting this output .. (9 Replies)
i know about ls, I know.... but some of our shares have a long messy list of acls and it is a lot to sort through.. without a grep option, unless you have a really nice one, is there a simple way to say: show me <USER> acl permissions on <SHARE> ? (1 Reply)
I have a list of files in a.txt file. For each of the files listed in that file, I would like to obtain the owner of the file and also, the permissions associated with that file.
If possible, the group the owner belongs to as well.
Can someone help me with a script to find that out. (1 Reply)
Hi, i'm using a Unix machine. I login as root. when i create new users using useradd -m <user_name> their home directories will be created in /home/ directory with default permissons of 750. i.e., drwxr-x---
how can i change these default permissions..??
which file to access and what changes i... (2 Replies)
Hi,
I have used expdp for datapump. The .dmp file is created by the "oracle" user.
my requirement is to make a zipped file of this .dmp file.
What i am trying to do is change the permissions of this .dmp file from 0640 to 0644 and then do a gzip and zip it. Is there any way i can change... (3 Replies)
Discussion started by: qwertyu
3 Replies
LEARN ABOUT DEBIAN
format::human::bytes
Format::Human::Bytes(3pm) User Contributed Perl Documentation Format::Human::Bytes(3pm)NAME
Format::Human::Bytes - Format a bytecount and make it human readable
VERSION
Version 0.05
SYNOPSIS
Ever showed 12345678 bytes to the user instead of just saying 11MB? This module returns you a printable string which is more readable by
humans than a simple bytecount.
use Format::Human::Bytes;
$readable = Format::Human::Bytes::base2($bytecount[,$decimals]);
$readable = Format::Human::Bytes::base10($bytecount[,$decimals]);
$readable = Format::Human::Bytes->base2($bytecount[,$decimals]);
$readable = Format::Human::Bytes->base10($bytecount[,$decimals]);
my $fhb = Format::Human::Bytes->new();
$readable = $fhb->base2($bytecount[,$decimals]);
$readable = $fhb->base10($bytecount[,$decimals]);
All functions do "intelligent" switching to the next unit, for example:
1000 => 1000B
[...]
8000 => 8000B
9000 => 9kB
The difference between 1000 bytes and 1500 bytes is usually bigger (for example because of a slow link) than between 95kB and 95,5kB. The
same applies to 8000kB vs. 9 MB and for the other units.
Depending on your usage, you may want to specify how many decimals should be shown (defaults to no decimals).
FUNCTIONS / METHODS
new
my $fhb = Format::Human::Bytes->new();
Creates and returns a Format::Human::Bytes - object.
base2
Callable as a function:
$readable = Format::Human::Bytes::base2($bytecount[,$decimals]);
Callable as a class method:
$readable = Format::Human::Bytes->base2($bytecount[,$decimals]);
Callable as a object method:
$readable = $fhb->base2($bytecount[,$decimals]);
Returns the correct readable form of the given bytecount.
Correct in this case means that 1kB are 1024 Bytes which is how computers see the world.
If you specify a decimal parameter, the result number will have the number of decimal numbers you specified.
base10
Callable as a function:
$readable = Format::Human::Bytes::base10($bytecount[,$decimals]);
Callable as a class method:
$readable = Format::Human::Bytes->base10($bytecount[,$decimals]);
Callable as a object method:
$readable = $fhb->base10($bytecount[,$decimals]);
Returns the incorrect readable form of the given bytecount.
Incorrect in this case means that 1kB is 1000 Bytes and 1 MB is 1000000 bytes which is how some (many) people see the world, but it's wrong
for computers.
If you specify a decimal parameter, the result number will have the number of decimal numbers you specified.
AUTHOR
Sebastian Willing, "<sewi at cpan.org>"
BUGS
Please report any bugs or feature requests to "bug-format-human-bytes at rt.cpan.org", or through the web interface at
<http://rt.cpan.org/NoAuth/ReportBug.html?Queue=Format-Human-Bytes>. I will be notified, and then you'll automatically be notified of
progress on your bug as I make changes.
SUPPORT
You can find documentation for this module with the perldoc command.
perldoc Format::Human::Bytes
You can also look for information at:
o RT: CPAN's request tracker
<http://rt.cpan.org/NoAuth/Bugs.html?Dist=Format-Human-Bytes>
o AnnoCPAN: Annotated CPAN documentation
<http://annocpan.org/dist/Format-Human-Bytes>
o CPAN Ratings
<http://cpanratings.perl.org/d/Format-Human-Bytes>
o Search CPAN
<http://search.cpan.org/dist/Format-Human-Bytes/>
HISTORY
The functions are in use since late 2003 or early 2004 but I didn't pack them for CPAN before 2009.
LICENSE
This program is free software; you can redistribute it and/or modify it under the same terms as Perl 5 itself.
perl v5.10.1 2010-04-08 Format::Human::Bytes(3pm)