converting the date field from dd/mm/yyyy to yyyy/mm/dd Post: 302298504

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Change Date from dd-mmm-yyyy to mm/dd/yyyy

I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks

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Perl script to extract last date field (yyyy/mm/dd)

Hi Friends, I've a special requirement, even though I know how to implement this using shell scripting, current requirement is PERL, in which I'm not much familiar !!!. I've a record, which has around 200 fields, out of which I need to extract only one date value from the 97th field (this...

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Sed: zero-padding dates (or: convert d/m/yyyy to dd/mm/yyyy)

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Sort field by date mm/dd/yyyy

Hello Group, I would like to sort the below file by date (first year then month and day) and I used the following command but it does not work sort -n -t"/" -k3 -k1 -k2 "sample original file" 12/28/2009,1.0353 12/31/2009,1.0357 12/30/2009,1.0364 12/29/2009,1.0366 12/24/2009,1.0386...

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change date format from yyyy/mm/dd to dd/mm/yyyy

(Attention: Green PHP newbie !) I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,...

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Converting date DD MM YYYY to DD MON YYYY

Hello, I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10) To extract the dates, I am using shell substrings, i.e.: read line ...

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Epoch date to YYYY/MM/DD or MM/DD/YYYY

I've seen a lot of posts on this and have tried the following: echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";' But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY. I am using bash and don't know...

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Date format YYYY/MM/DD to DD/MM/YYYY

I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY. When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD file...

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xmlindent

xmlindent(1)															      xmlindent(1)

NAME

       xmlindent - XML stream reformatter

SYNTAX

       xmlindent [-o output file] [-i indent level] [-l max columns] [-n newline position] [-t] [-c] [-f] [-w] [-h] [-v]

DESCRIPTION

       XML Indent is a XML stream reformatter written in ANSI C. It is analogous to GNU indent.

OPTIONS

       -o output file
	      Write indented XML to output file

       -i indent level
	      Indent each level indent level spaces deeper

       -l max columns
	      Wrap lines longer than max columns

       -t     Use tabs instead of spaces

       -nas   Suppress newline after start-tag

       -nae   Suppress newline after end-tag

       -nbs   Suppress newline before start-tag

       -nbe   Suppress newline before end-tag

       -f     Force newline on elements without children

       -w     Overwrite original file

       -v     Show version

       -h     Show command line help

AUTHORS

       Pekka Enberg <penberg@iki.fi>
       Thomas Fischer <th.fischer@gmx.net> (man page)

SEE ALSO

       indent(1)

Thomas Fischer							      0.2.17							      xmlindent(1)

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Change Date from dd-mmm-yyyy to mm/dd/yyyy

Discussion started by: stringzz

2. Shell Programming and Scripting

Perl script to extract last date field (yyyy/mm/dd)

Discussion started by: ganapati

3. Shell Programming and Scripting

Sed: zero-padding dates (or: convert d/m/yyyy to dd/mm/yyyy)

Discussion started by: jgrogan

4. UNIX for Dummies Questions & Answers

Sort field by date mm/dd/yyyy

Discussion started by: csierra