converting the date field from dd/mm/yyyy to yyyy/mm/dd Post: 302298504

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Change Date from dd-mmm-yyyy to mm/dd/yyyy

I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks

2. Shell Programming and Scripting

Perl script to extract last date field (yyyy/mm/dd)

Hi Friends, I've a special requirement, even though I know how to implement this using shell scripting, current requirement is PERL, in which I'm not much familiar !!!. I've a record, which has around 200 fields, out of which I need to extract only one date value from the 97th field (this...

3. Shell Programming and Scripting

Sed: zero-padding dates (or: convert d/m/yyyy to dd/mm/yyyy)

4. UNIX for Dummies Questions & Answers

Sort field by date mm/dd/yyyy

Hello Group, I would like to sort the below file by date (first year then month and day) and I used the following command but it does not work sort -n -t"/" -k3 -k1 -k2 "sample original file" 12/28/2009,1.0353 12/31/2009,1.0357 12/30/2009,1.0364 12/29/2009,1.0366 12/24/2009,1.0386...

5. Shell Programming and Scripting

change date format from yyyy/mm/dd to dd/mm/yyyy

(Attention: Green PHP newbie !) I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,...

6. Shell Programming and Scripting

Converting date DD MM YYYY to DD MON YYYY

Hello, I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10) To extract the dates, I am using shell substrings, i.e.: read line ...

7. Shell Programming and Scripting

Converting Date from YYYYMMDD to DD-MON-YYYY

Hi , I need to convert date from YYYYMMDD to DD-MON-YYYY e.g 20111214 to 14-Dec-2011 Please help.

8. Shell Programming and Scripting

Date conversion help from dd/mm/yyyy to dd/Mon/yyyy i.e. 28/10/2012 to 28/Oct/2012

Hi I have a problem with Date format in my code. 1st I am trying to convert today's date to yesterday's using YESTERDAY3=`perl -e '@y=localtime(time()-86400); printf "%04d/%02d/%02d",$y+1900,$y+1,$y;$y;'` And once it is done I am trying to using the yesterday date in a grep command to...

9. UNIX for Dummies Questions & Answers

Epoch date to YYYY/MM/DD or MM/DD/YYYY

I've seen a lot of posts on this and have tried the following: echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";' But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY. I am using bash and don't know...

10. Shell Programming and Scripting

Date format YYYY/MM/DD to DD/MM/YYYY

I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY. When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD file...

LEARN ABOUT HPUX

wrap-and-sort

WRAP-AND-SORT(1)					      General Commands Manual						  WRAP-AND-SORT(1)

NAME

       wrap-and-sort - wrap long lines and sort items in Debian packaging files

SYNOPSIS

       wrap-and-sort [options]

DESCRIPTION

       wrap-and-sort  wraps the package lists in Debian control files. By default the lists will only split into multiple lines if the entries are
       longer than 80 characters. wrap-and-sort sorts the package lists in Debian control files and all .install files. Beside that  wrap-and-sort
       removes trailing spaces in these files.

       This  script should be run in the root of a Debian package tree. It searches for control, control.in, copyright, copyright.in, install, and
       *.install in the debian directory.

OPTIONS

       -h, --help
	      Show this help message and exit.

       -a, --wrap-always
	      Wrap all package lists in the Debian control file even if the entries are shorter than 80 characters and could fit in one line line.

       -s, --short-indent
	      Only indent wrapped lines by one space (default is in-line with the field name).

       -b, --sort-binary-packages
	      Sort binary package paragraphs by name.

       -k, --keep-first
	      When sorting binary package paragraphs, leave the first one at the top.  Unqualified debhelper(7) configuration files are applied to
	      the first package.

       -n, --no-cleanup
	      Do not remove trailing whitespaces.

       -d path, --debian-directory=path
	      Location of the debian directory (default: ./debian).

       -f file, --file=file
	      Wrap  and sort only the specified file.  You can specify this parameter multiple times.  All supported files will be processed if no
	      files are specified.

       -v, --verbose
	      Print all files that are touched.

AUTHORS

       wrap-and-sort and this manpage have been written by Benjamin Drung <bdrung@debian.org>.

       Both are released under the ISC license.

DEBIAN
								 Debian Utilities						  WRAP-AND-SORT(1)

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Change Date from dd-mmm-yyyy to mm/dd/yyyy

Discussion started by: stringzz

2. Shell Programming and Scripting

Perl script to extract last date field (yyyy/mm/dd)

Discussion started by: ganapati

3. Shell Programming and Scripting

Sed: zero-padding dates (or: convert d/m/yyyy to dd/mm/yyyy)

Discussion started by: jgrogan

4. UNIX for Dummies Questions & Answers

Sort field by date mm/dd/yyyy

Discussion started by: csierra