I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
Hi Friends,
I've a special requirement, even though I know how to implement this using shell scripting, current requirement is PERL, in which I'm not much familiar !!!.
I've a record, which has around 200 fields, out of which I need to extract only one date value from the 97th field (this... (1 Reply)
Hi all
I have some pipe-separated data in the form:
5/12/2008 00:00:00|31/1/2009 00:00:00|SOMESTUFF|OTHERSTUFF
12/31/2008 00:00:00|15/1/2009 00:00:00|MORESTUFF|REMAININGSTUFF
1/1/1023 00:00:00|16/5/2047 00:00:00|THEREST|YETMORE
I need to zero-pad the single-digit days and months, using... (3 Replies)
Hello Group,
I would like to sort the below file by date (first year then month and day) and I used the following command but it does not work
sort -n -t"/" -k3 -k1 -k2
"sample original file"
12/28/2009,1.0353
12/31/2009,1.0357
12/30/2009,1.0364
12/29/2009,1.0366
12/24/2009,1.0386... (6 Replies)
(Attention: Green PHP newbie !)
I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Hello,
I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10)
To extract the dates, I am using shell substrings, i.e.:
read line
... (4 Replies)
Hi I have a problem with Date format in my code.
1st I am trying to convert today's date to yesterday's using
YESTERDAY3=`perl -e '@y=localtime(time()-86400); printf "%04d/%02d/%02d",$y+1900,$y+1,$y;$y;'`
And once it is done I am trying to using the yesterday date in a grep command to... (3 Replies)
I've seen a lot of posts on this and have tried the following:
echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";'
But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY.
I am using bash and don't know... (4 Replies)
I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY.
When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD
file... (3 Replies)
Discussion started by: Roozo
3 Replies
LEARN ABOUT ULTRIX
cut
cut(1) General Commands Manual cut(1)Name
cut - cut out selected fields of each line of a file
Syntax
cut -clist [file1 file2...]
cut -flist [-dchar] [-s] [file1 file2...]
Description
Use the command to cut out columns from a table or fields from each line of a file. The fields as specified by list can be fixed length,
that is, character positions as on a punched card (-c option), or the length can vary from line to line and be marked with a field delim-
iter character like tab (-f option). The command can be used as a filter. If no files are given, the standard input is used.
Use to make horizontal ``cuts'' (by context) through a file, or to put files together in columns. To reorder columns in a table, use and
Options
list Specifies ranges that must be a comma-separated list of integer field numbers in increasing order. With optional - indicates
ranges as in the -o option of nroff/troff for page ranges; for example, 1,4,7; 1-3,8; -5,10 (short for 1-5,10); or 3- (short
for third through last field).
-clist Specifies character positions to be cut out. For example, -c1-72 would pass the first 72 characters of each line.
-flist Specifies the fields to be cut out. For example, -f1,7 copies the first and seventh field only. Lines with no field delim-
iters are passed through intact (useful for table subheadings), unless -s is specified.
-dchar Uses the specified character as the field delimiter. Default is tab. Space or other characters with special meaning to the
shell must be quoted. The -d option is used only in combination with the -f option, according to XPG3 and SVID2/SVID3.
-s Suppresses lines with no delimiter characters. Unless specified, lines with no delimiters are passed through untouched.
Either the -c or -f option must be specified.
Examples
Mapping of user IDs to names:
cut -d: -f1,5 /etc/passwd
To set name to the current login name for the csh shell:
set name=`who am i | cut -f1 -d" "`
To set name to the current login name for the sh, sh5, and ksh shells:
name=`who am i | cut -f1 -d" "`
Diagnostics
"line too long" A line can have no more than 511 characters or fields.
"bad list for c/f option"
Missing -c or -f option or incorrectly specified list. No error occurs if a line has fewer fields than the list calls
for.
"no fields" The list is empty.
See Alsogrep(1), paste(1)cut(1)